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4 years ago

Does anyone know this???

Mathematics

1 answer:

Grace [21]4 years ago

8 0

Answer:

see explanation

Step-by-step explanation:

Since the triangles are congruent then corresponding angles are congruent.

Thus ∠D = ∠A and substituting values

2x = x + 31 ( subtract x from both sides )

x = 31

Hence

∠A = x + 31 = 31 + 31 = 62

∠D = 2x = 2 × 31 = 62

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Help........................

GaryK [48]

Answer:

Step-by-step explanation:

6 0

3 years ago

a rhombus as an area of 72 ft and the product of the diagonals is 144. What is the length of each diagonal?

SashulF [63]

A = (1/2)(x)(y)

Let x = diagonal 1

Let y = diagonal 2

The product of xy = 144.

This means that x = 12 and y = 12.

So, 12 • 12 = 144

Each diagonal is 12 feet.

Prove:

72 feet = (1/2)(12)(12) feet

72 feet = (1/2)(144) feet

72 feet = 72 feet

6 0

4 years ago

I need help with this..

Misha Larkins [42]

Answer:

a0) 2

x<0

a1) x

0≤x<3

a2) 3

x≥3

Step-by-step explanation:

As shown in the given graph

function of y is a straight line at y=2 line till x=0

hence a0:

y= 2 for x<0

Then function becomes linear line from x=0 till x=3

hence a1:

y= x for 0≤x<3

Now after that graph of function y again shift to straight line from x=3 onward with y-axis value of 3

hence a2:

y= 3 for x≥3 !

8 0

3 years ago

The difference between the square of two numbers is 11. Twice the square of the first number increased by the square of the seco

jeyben [28]

Answer:

Below in bold.

Step-by-step explanation:

x^2 - y^2 = 11

2x^2 + y^2 = 97

From the first equation:

y^2 = x^2 - 11

Substituting in the second equation:

2x^2 + x^2 - 11 = 97

3x^2 = 108

x^2 = 36

x = 6, -6.

Substituting for x in the first equation:

(6)^2 - y^2 = 11

y^2 = 36 - 11 = 25

y = 5, -5.

6 0

3 years ago

Willis tower in Chicago is 1450 feet tall. The John Hancock Center in Chicago is 1127 feet tall. Suppose you are asked to build

gayaneshka [121]

Answer:

Small Scale replica of John Hancock tower is approximately 2.33 m.

Step-by-step explanation:

Given:

Height of Willis tower = 1450 ft

Height of John Hancock Center = 1127 ft

Small Scale replica of Willis tower = 3 m

We need to find Small Scale replica of John Hancock tower.

First we will find the per meter scale of Willis tower and then using the same we will use to find the Small Scale replica height of John Hancock tower.

For 3 meter scaling = 1450 ft

So for 1 meter scaling = Number of foots in 1 meter Scaling

By Using Unitary method we get;

Number of foots in 1 meter Scaling = $\frac{1450}{3} = 483.333 \ ft$

Now we had 1 meter scaling as 483.333 ft and we need to find meter scaling for 1127.

So again Using Unitary method we get;

Small Scale replica of John Hancock = $\frac{1127}{483.333} = 2.331 \ m$

Rounding to nearest hundred we get;

Small Scale replica of John Hancock tower is approximately 2.33 m.

8 0

3 years ago