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KonstantinChe [14]
3 years ago
12

Add or subtract the following mixed numbers using the first method. Be sure your answers are in mixed number format and reduced

to lowest terms. 3 3/8 + 2 1/6 =
Mathematics
1 answer:
Paraphin [41]3 years ago
5 0
We have the number here are 3 3/8 and 2 1/6
by using the first method,
multiplying 3/8 with 3/3 and 1/6 with 4/4 we get 9/24 and 4/24 so,
3 9/24 + 2 4/24 = (3+2) and (9/24 + 4/24)
when adding 3 and 2 we get 5 and adding 9/24 and 4/24 we get 13/24
so the answer is 5 and 13/24
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Type the slope-intercept equation
natulia [17]

Answer:

y= -2x +1

Step-by-step explanation:

<u>slope- intercept form</u><u>:</u>

y= mx +c, where m us the gradient and c is the y-intercept.

Let's find the value of m first using the gradient formula.

Gradient= \frac{y1 - y2}{x1 - x2}

m =  \frac{ - 3 - 3}{2 - ( - 1)}  \\ m =  \frac{ - 6}{2 + 1}  \\ m =  \frac{ - 6}{3}  \\ m =  - 2

y= -2x +c

To find the value of c, substitute a pair of coordinates.

When x= -1, y=3,

3= -2(-1) +c

3= 2 +c

c= 3 -2

c= 1

Thus the equation of the line is y= -2x +1.

4 0
3 years ago
Evaluate ​f(x)=2x- 1 at the given value of x.<br><br> ​f(1​)<br><br> f(1)=
USPshnik [31]
F(1)=2(1)-1
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7 0
3 years ago
A data set lists weights​ (lb) of plastic discarded by households. The highest weight is 5.31 ​lb, the mean of all of the weight
a_sh-v [17]

Answer:

a) The difference is of 3.222 lbs.

b) 1.64 standard deviations.

c) Z = 1.64

d) Not significant, as the z-score of 1.64 is between -2 and 2.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The mean of all of the weights is x=2.088 ​lb, and the standard deviation of the weights is s=1.968 lb.

This means that \mu = 2.088, \sigma = 1.968

a. What is the difference between the weight of 5.31 lb and the mean of the​ weights?

This is X - \mu = 5.31 - 2.088 = 3.222

The difference is of 3.222 lbs.

b. How many standard deviations is that​ [the difference found in part​ (a)]?

This is the z-score. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{5.31 - 2.088}{1.968}

Z = 1.64

1.64 standard deviations.

c. Convert the weight of 5.31 lb to a z score.

Z = 1.64, as found above.

d. If we consider weights that convert to z scores between −2 and 2 to be neither significantly low nor significantly​ high, is the weight of 5.31 lb​ significant?

Not significant, as the z-score of 1.64 is between -2 and 2.

5 0
3 years ago
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olganol [36]
The answer is Answer: y=−4x−10
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algol [13]
Answer : 14.5≥ g+ 1.5
5 0
3 years ago
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