Answer:
A question is never clear
Answer:
C: Take infected amphibians and assign them to two populations. Leave one population alone; inoculate the other with Jl. Measure the rate at which infection proceeds in both populations.
Explanation:
In scientific investigations, the best way to determine the effect of certain experimental factor on the population of study is to have a baseline for comparison. This is usually referred to as controlled experiment.
<em>In the case of the observation that chytrid infection in amphibians seems to be inhibited by Janthinobacterium lividum, the best way experimental design is to get a population of amphibians suffering from the disease, divide them into two groups and subject them to the same conditions except the introduction of Janthinobacterium lividum to the skin of one of the groups.</em>
<em>A suitable method can thereafter be employed to measure the rate at which infection proceeds in both population. If indeed, the bacterium has the capacity to inhibit the infection, the rate of infection in the group with the bacterium will be significantly less than that of the group without the bacterium. </em>
The correct option is C.
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Answer: Metabolic alkalosis
Explanation: Metabolic alkalosis refers to a metabolic condition in which the tissue’s pH is increased above the normal range (7.35–7.45). This occurs as a result of decrease in the concentration of Hydrogen ion, which results to increased bicarbonate in the body system. It can also be caused by direct increase in the bicarbonate concentrations.
Answer:
The probability is 1/2
Explanation:
Heterozygous for sickle cell allele is AS
Homozygous allele is SS
AS SS
The offspring formed include
AS, AS, SS, SS
The probability of their children being carriers include
Number of AS/ Total number of offspring
= 2/4 =1/2 or 0.5