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inessss [21]
3 years ago
12

Can someone please figure this out for me because I don't understand it.

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
8 0
The answer would be 'b'
Now, here Luke walks total 2¼ miles but his friend's home is ¼ mile. So, number of trips he makes = Total miles walked ÷ Distance to his friend's home
= 2¼ ÷ ¼ = 9
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3 years ago
Keenan will run 2.5 miles from his house to Jared’s house. He plans to hang out for 45 minutes before walking home. If he can ru
jenyasd209 [6]

Answer:

Kennan will be from home approximately an hour and 48 minutes.

Step-by-step explanation:

We must know that total time (t_{T}) that Keenan will be from home is the sum of run (t_{R}), hang out (t_{H}) and walk times (t_{W}), measured in hours:

t_{T} = t_{R}+t_{H}+t_{W}

If Keenan runs and walks at constant speed, then equation above can be expanded:

t_{T} = \frac{x_{R}}{v_{R}}+t_{H}+ \frac{x_{W}}{v_{W}}

Where:

x_{R}, x_{W} - Run and walk distances, measured in miles.

v_{R}, v_{W} - Run and walk speeds, measured in miles per hour.

Given that x_{R}=x_{W} = 2.5\,mi, v_{R} = 6\,\frac{mi}{h}, v_{W} = 4\,\frac{mi}{h} and t_{H} = 0.75\,h, the total time is:

t_{T} = \frac{2.5\,mi}{6\,\frac{mi}{h} } + 0.75\,h+\frac{2.5\,mi}{4\,\frac{mi}{h} }

t_{T} = 1.792\,h (1\,h\,48\,m)

Kennan will be from home approximately an hour and 48 minutes.

7 0
3 years ago
Which statement is correct?
abruzzese [7]

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gvhbh

Step-by-step explanation:.

3 0
3 years ago
Ok so can someone pls help me on this. It’s math, and pls explain.
Anika [276]

F.v*king ki11 yourself, you gay piece of $.h1t. Gay b17ches like you burn in hell

3 0
3 years ago
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