Answer:
p = -1 q = -4
Step-by-step explanation:
a system of eq and solve for p and q ??? can do :)
Eq. 1) 8p + 2q = - 16
Eq. 2) 2p - q = 2
use Eq .2 and solve for q
2p - 2 = q
plug into Eq.1 with q
8p +2(2p - 2) = - 16
8p +4p -4 = -16
12p = - 12
p = -1
plug -1 into Eq. 1 for p and solve for q
8(-1) + 2q = - 16
-8 + 2q = - 16
2q = -8
q = -4
X = tuna, y = BLT
x + y = 30
6x + 9y = 240
3y = 60
y = 20
x = 10
20 BLTs for $2.50, 10 tuna for $1.50
Answer:
Is there supposed to be a graph somewhere?
(1,-1)
(-4,2)
(-2,1)
I believe these will work
By using pythagoras theorem where
(Base)^2 +(perpedicular)^2 = (hypotenuse)^2
So,
(5)^2 +(12)^2 = (hypotenuse)^2
25 + 144 = (hypotenuse)^2
169 = (hypotenuse)^2
13 = hypotenuse
So, hypotenuse = 13
