A sodium ion symbol is written as Na^+.
Answer:
One kind is called living things. Living things eat, breathe, grow, move, reproduce and have senses. The other kind is called nonliving things. Nonliving things do not eat, breathe, grow, move and reproduce.
There are 19.5 g Na in 71.4 g NaHCO₃
Calculate the <em>molecular mass of NaHCO₃</em>.
1 Na = 1 × 22.99 u = 22.99 u
1 H = 1 × 1.008 u = 1.008 u
1 C = 1 × 12.01 u = 12.01 u
3 O = 3 × 16.00 u = <u>48.00 u
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TOTAL = 84.008 u
So, there are 22.99 g of Na in 84.008 g NaHCO₃.
∴ Mass of Na = 71.4 g NaHCO₃ × (22.99 g Na/84.008 g NaHCO₃) = 19.5 g Na
Answer:
91.4°C
Explanation:
Gay - Lussac Law => T ∝ P => T = kP => k = T/P with volume (V) and mass (n) constant.
For two different Temperature (T)-Pressure (P) conditions
k₁ = k₂ => T₁/P₁ = T₂/P₂ => T₂ = T₁(P₂/P₁)
T₁ = 55°C = (55 + 273)K = 328K
P₁ = 965 mmHg
T₂ = ?
P₂ = 850 mmHg
T₂ = T₁(P₂/P₁) = 328K(850 mmHg/965 mmHg) = 364K = (364 - 273)°C = 91.4°C
Answer is: 15.30 kilojoules of heat are needed to completely vaporize C₄H₁₀<span>.
m(</span>C₄H₁₀) = 42.8 g.
M(C₄H₁₀) = 74.12 g/mol.
n(C₄H₁₀) = m(C₄H₁₀) ÷ M(C₄H₁₀).
n(C₄H₁₀) = 42.8 g ÷ 74.12 g/mol.
n(C₄H₁₀) = 0.577 mol.
Q = n(C₄H₁₀) · ΔHvap.
<span>Q = 0.577 mol </span>· 26.5 kJ/mol.
<span>Q = 15.30 kJ, heat of butane.
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