1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Arturiano [62]
3 years ago
10

Mikes rents a car for a total of £445 the rental charges are £145 for first day and £60 per day after that for how many days did

he mike rent the car
Mathematics
1 answer:
zimovet [89]3 years ago
7 0
So, I'm not use to that type of currency, but I can still help you.
The equation would be:
145 + 60(d-1) = 445
Now since it is 60  per day after that, the first day would not be charge, the second would but you would not charge it more.
145 + 60d - 60 = 445
Add like terms
85 + 60d = 445
-85               -85
60d= 360
d= 6
You can even check using a table/ coordinates. x= days, y=money
(1, 145), (2, 205), (3, 265), (4, 325), (5, 385), (6, 445).
You might be interested in
What is the multiplicative inverse of One half
maks197457 [2]

Answer:

2

Step-by-step explanation:

The multiplicative inverse of 1/2 is 2. To determine the multiplicative inverse of a number, we use the following rule: The multiplicative inverse...

6 0
3 years ago
Which direction does the graph of the equation shown below open?
Mnenie [13.5K]
Option A.

you can rewrite the equation as x = y^2 / 4 + y - 1

If you conserve the traditional x-axis and y-axis, the parabola opens to the right (the symetry axis is parallel to x and the function grows as y grows).
3 0
3 years ago
Read 2 more answers
Write any Quetion for the following transformation of Y equals X a vertical compression by factor of 1/4
irina [24]
Suppose that X is a vertical segment that lies on the y-axis with its beginning at origin and ending at the point (0,4). Then the length of this segment is 4 units.
If you vertically compress this segment by factor of 1/4 with the centre of compression at the origin, you recieve a segment that also lies on the y-axis with its beginning at origin and ending at the point (0,1) (the length of this image segment is 1 unit).
So, the question is: if a segment that lies on the y-axis with its beginning at origin and ending at the point (0,4) is vertically compressed <span>by factor of 1/4 with the centre of compression at the origin, what is the image of this transformation?
</span>





7 0
3 years ago
Find the measure of angle RPQ help me please thank u​
xenn [34]

Answer:

\boxed {54^{o}}

Step-by-step explanation:

By Inscribed Angle Theorem, the value of an inscribed angle enclosed by an arc is the half the value of that arc.

⇒ ∠RPQ = 108°/2

⇒ ∠RPQ = 54°

3 0
1 year ago
If the two triangles shown below are similar based on the giveninformation, complete the similarity statement, otherwise choose
SVETLANKA909090 [29]

1) Two triangles are similar if they have congruent angles and proportional sides (for each corresponding leg).

2) So let's check whether there are similar triangles by setting a proportion:

\begin{gathered} \frac{HC}{CA}=\frac{JH}{CB} \\ \frac{9}{18}=\frac{7}{14} \\ Simplify\text{ both:} \\ \frac{1}{2}=\frac{1}{2} \end{gathered}

3) So yes they are similar, i.e. ΔCAB ~ΔHGJ

5 0
1 year ago
Other questions:
  • 12. The ratio of clown fish to angelfish at a pet store is 5:4. The ratio of
    6·2 answers
  • What are the zeros of f(x) = x2 - 8x + 16?
    11·1 answer
  • Hi I need help please
    13·2 answers
  • Help please!!!!!!!!!!!!!!!
    9·1 answer
  • I need help on this question
    6·1 answer
  • Could someone answer these problems ?
    14·2 answers
  • Selma spent
    11·1 answer
  • The incenter of a triangle is the point of concurrency of the angle bisectors. Does a rectangle have an incenter?
    15·1 answer
  • What is the domain of this function?<br> (0, 2), (1, 3), (2, 4), (3, 5), (4, 6)
    6·2 answers
  • Divide 12.73 by 8 and round off correct to two decimal places​
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!