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aev [14]
3 years ago
6

Solve for x. 4(2x + 1) = 3(x + 8)

Mathematics
1 answer:
il63 [147K]3 years ago
8 0
4(2x+1) = 3(x+8)
8x + 4 = 3x + 24
5x = 20
∴x = 4
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ASAP ILL GIVE BRAINLIEST IF UR RIGHT!!! The radius of the cone is 5 in and y = 13 in. What is the volume of the cone in terms of
Blababa [14]

Answer: V = 100\pi in^{3} (third option)

Given Information:

  • V = \frac{1}{3}\pi r^{2} h <-- volume formula.
  • r = 5
  • y = 13
  • <em>h = ?</em>

To find h...

  • h, r, and y make a right triangle.
  • h and r are the two legs, y is the hyptenuse.
  • h^{2} + r^{2} = y^{2}
  • h^{2} + 5^{2} = 13^{2}
  • h^{2} + 25 = 169
  • h^{2} = 144
  • h = 12

Use formula:

  • V = \frac{1}{3}\pi r^{2} h
  • V = \frac{1}{3} \pi (5)^{2} (12)
  • V = \frac{1}{3} \pi (25)(12)
  • V = \frac{1}{3} \pi (300)
  • V = 100\pi
7 0
3 years ago
Read 2 more answers
The lenght of an arc in a circle with radius 8 inches is 3.2π. determine the measure of the arc​
aleksandrvk [35]

Answer:

72

Step-by-step explanation:

32pi×360/2pi(8)=72

central angle= arc length 360/2pi×r

8 0
2 years ago
10. 5(3-9b) = 3(-15b – 2)
olga2289 [7]

Answer:

No Solution

Explanation:

5(3 - 9b) = 3(-15b – 2)

Expand

5(3 - 9b): 15 - 45b

3(-15b - 2): -45b - 6

15 - 45b = -45b - 6

Subtract 5 From Both Sides

15 - 45b - 15 = -45b - 6 - 15

Simplify

-45b = -45b - 21

Add 15b To Both Sides

-45b + 15b = -45b - 21 + 15b

Simplify

0 = -21

No Solution

8 0
3 years ago
Determine the location and values of the absolute maximum and absolute minimum for given function : f(x)=(‐x+2)4,where 0&lt;×&lt
brilliants [131]

Answer:

Where 0 < x < 3

The location of the local minimum, is (2, 0)

The location of the local maximum is at (0, 16)

Step-by-step explanation:

The given function is f(x) = (x + 2)⁴

The range of the minimum = 0 < x < 3

At a local minimum/maximum values, we have;

f'(x) = \dfrac{(-x + 2)^4}{dx}  = -4 \cdot (-x + 2)^3 = 0

∴ (-x + 2)³ = 0

x = 2

f''(x) = \dfrac{ -4 \cdot (-x + 2)^3}{dx}  = -12 \cdot (-x + 2)^2

When x = 2, f''(2) = -12×(-2 + 2)² = 0 which gives a local minimum at x = 2

We have, f(2) = (-2 + 2)⁴ = 0

The location of the local minimum, is (2, 0)

Given that the minimum of the function is at x = 2, and the function is (-x + 2)⁴, the absolute local maximum will be at the maximum value of (-x + 2) for 0 < x < 3

When x = 0, -x + 2 = 0 + 2 = 2

Similarly, we have;

-x + 2 = 1, when x = 1

-x + 2 = 0, when x = 2

-x + 2 = -1, when x = 3

Therefore, the maximum value of -x + 2, is at x = 0 and the maximum value of the function where 0 < x < 3, is (0 + 2)⁴ = 16

The location of the local maximum is at (0, 16).

5 0
3 years ago
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Ivenika [448]

Answer:

The relationship is proportional. The constant of proportionality is 20. It represents how many meters the horse runs per second per second. Equation is d=20t

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3 years ago
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