7) A
8) C
9) B
I’m not certain but I hope this helps you...sorry if I got it wrong!!
Answer:
Step-by-step explanation:
Hello!
The objective is to estimate the average time a student studies per week.
A sample of 8 students was taken and the time they spent studying in one week was recorded.
4.4, 5.2, 6.4, 6.8, 7.1, 7.3, 8.3, 8.4
n= 8
X[bar]= ∑X/n= 53.9/8= 6.7375 ≅ 6.74
S²= 1/(n-1)*[∑X²-(∑X)²/n]= 1/7*[376.75-(53.9²)/8]= 1.94
S= 1.39
Assuming that the variable "weekly time a student spends studying" has a normal distribution, since the sample is small, the statistic to use to perform the estimation is the student's t, the formula for the interval is:
X[bar] ±
* (S/√n)

6.74 ± 2.365 * (1.36/√8)
[5.6;7.88]
Using a confidence level of 95% you'd expect that the average time a student spends studying per week is contained by the interval [5.6;7.88]
I hope this helps!
Hello,
Answer D.
====================
Answer: 10?
Step-by-step explanation: Just divide 20/2 and you get the answer. Ight Ima head out
Well, since you didn't attach the options. I will try to simplify the problem for you.⬇
Problem➡8/9 ÷2/3
~How to solve it ⬇
8(3) / 9(2) = 24/18
So, that means that your answer might have to be
1 1/3~