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Sever21 [200]
3 years ago
14

What is the measure of DG?

Mathematics
1 answer:
Masja [62]3 years ago
7 0

Answer:

170

Step-by-step explanation:

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At the beginning of the day, stock XYZ opened at $3.15. At the end of the day, it closed at $2.87. What is the rate of change of
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-8.9%

Step-by-step explanation:


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3 years ago
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Suppose the function f(t) = 95 cosine (StartFraction pi Over 10 EndFraction t) + 120 models the height of a seat on a Ferris whe
drek231 [11]

Answer:

im not 100% bit i think its 95ft

Step-by-step explanation:

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3 years ago
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Solve for u<br> 5+4u=11<br> Simplify your answer as much as possible
r-ruslan [8.4K]

Answer:

u = 1.5

Step-by-step explanation:

5+4u=11

-5        -5

4u = 6

/4      /4

u=1.5

5 0
3 years ago
What is the greatest common factor of 44c^5, 22c^3 and 11c^4
Alexxandr [17]

\text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3

<em><u>Solution:</u></em>

Given that, we have to find the greatest common factor of 44c^5, 22c^3 , 11c^4

The greatest number that is a factor of two (or more) other numbers.

When we find all the factors of two or more numbers, and some factors are the same ("common"), then the largest of those common factors is the Greatest Common Factor

\underline{\text{ GCF of } 44c^5, 22c^3 , 11c^4 :}

First find the GCF of numbers and then find the GCF of variables and then multiply them together

<em><u>Step 1: GCF of 44, 22 and 11</u></em>

The factors of 11 are: 1, 11

The factors of 22 are: 1, 2, 11, 22

The factors of 44 are: 1, 2, 4, 11, 22, 44

11 is the greatest factor that is common in above three list

Then the greatest common factor is 11

\text{ Step 2: GCF of }c^5, c^3 , c^4

c^5 = c^3 \times c^2\\\\c^3 = c^2 \times c^1 \text{ or } c^3\\\\c^4 = c^3 \times c^1

Thus the greatest common factor is c^3

Step 3: Multiply the GCF of 44, 22, 11 and GCF of c^5, c^3 , c^4

\text{ GCF of } 44c^5, 22c^3 , 11c^4 = 11 \times c^3 = 11c^3

Thus \text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3

8 0
3 years ago
H(j + i) - k5 + h<br> when h = 3, i = 4, j = 2, and k = 1<br> pls put how you did it
VikaD [51]

Answer:

16

Step-by-step explanation:

First you want to plug in all the numbers where the letters are

h ( j + i )- k(5) + h

3 ( 2 + 4 )- 1(5) + 3

After this step you will have to distribute the 3 outside the parenthesis. Which you do by multiplying everything in side the parenthesis by the outside number which is three.

6 + 12 - 1(5) + 3

Then you just follow PEMDAS to solve for the rest

6 + 12 - 5 + 3

18 - 5 + 3

13 + 3

16

6 0
3 years ago
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