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3 years ago

What is the measure of DG?

Mathematics

1 answer:

Masja [62]3 years ago

7 0

Answer:

170

Step-by-step explanation:

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Thee vertex of a parabola is (-5,2), and its focus is (-1,2). What is the standard form of the parabola?

Alla [95]

Check the picture below. So the parabola looks more or less like so.

$\bf \textit{horizontal parabola vertex form with focus point distance} \\\\ 4p(x- h)=(y- k)^2 \qquad \begin{cases} \stackrel{vertex}{(h,k)}\qquad \stackrel{focus~point}{(h+p,k)}\qquad \stackrel{directrix}{x=h-p}\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ \stackrel{"p"~is~negative}{op ens~\supset}\qquad \stackrel{"p"~is~positive}{op ens~\subset} \end{cases} \\\\[-0.35em] ~\dotfill$

$\bf \begin{cases} h=-5\\ k=2\\ p=4 \end{cases}\implies 4(4)[x-(-5)]=[y-2]^2\implies 16(x+5)=(y-2)^2 \\\\\\ x+5=\cfrac{1}{16}(y-2)^2\implies x = \cfrac{1}{16}(y-2)^2-5$

6 0

3 years ago

Read 2 more answers

At noon, train A leaves Bridgton heading

Snezhnost [94]

I'd say maybe by 5:30 b would

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3 years ago

What is the slope-intercept equation of the line below?

yKpoI14uk [10]

Slope is known as rise over run. Because the line is pointing "\", it is negative.

The rise, the distance from one point to another, specifically from (0,4) to (1,1) is 3, as 4-1=3. your run is 1-0=1.

So your rise over run is -3/1 or, -3.

Your y-int is where when x=0, y=?

In this case y=4 when x=0.

Your equation is

y=-3x+4

5 0

2 years ago

Is 15 ft, 36 ft, 39 ft a right triangle?

Nina [5.8K]

Use the pythagoream theorem to check. a^2+b^2=c^2

a=15 b=36 c= 39

225+1296=1521

The equation is true so it is a right triangle.

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3 years ago

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The water reaches a max height when the horizontal distance from the firefighter to the building is approximately __m. Round to

elena-s [515]

The horizontal distance from the firefighter at which the maximum height of water occurs is 10.83m

<u>Explanation:</u>

Given:

h(x) = -0.026x² + 0.563x + 3

where,

h(x) is the height of the water

Initial speed, u = 14m/s

angle, θ = 30°

(a)

Horizontal distance = ?

h(x) = ax² + bx + c

the vertex is found at x = -b/2a

where,

x = distance to the maximum height

As compared to the equation given:

a = -0.026

b = 0.563

Thus,

$x = \frac{-0.563}{2 X -0.026} \\\\x = \frac{0.563}{0.052}\\ \\x = 10.83m$

Therefore, horizontal distance from the firefighter at which the maximum height of water occurs is 10.83m

3 0

3 years ago