If v = ibh find v when i =8,b = 6 and h = 4

The sum of two polynomials is 8d5 – 3c3d2 + 5c2d3 – 4cd4 + 9. If one addend is 2d5 – c3d2 + 8cd4 + 1, what is the other addend?

Anit [1.1K]

Answer: The correct option is A.

Step-by-step explanation: We are given a polynomial which is a sum of other 2 polynomials.

We are given the resultant polynomial which is : $8d^5-3c^3d^2+5c^2d^3-4cd^4+9$

One of the polynomial which are added up is : $2d^5-c^3d^2+8cd^4+1$

Let the other polynomial be 'x'

According to the question:

$8d^5-3c^3d^2+5c^2d^3-4cd^4+9=x+(2d^5-c^3d^2+8cd^4+1)$

$x=8d^5-3c^3d^2+5c^2d^3-4cd^4+9-(2d^5-c^3d^2+8cd^4+1)$

Solving the like terms in above equation we get:

$x=(8d^5-2d^5)+(-3c^3d^2+c^3d^2)+(5c^2d^3)+(-4cd^4-8cd^4)+(9-1)$

$x=6d^5-2c^3d^2+5c^2d^3-12cd^4+8$

Hence, the correct option is A.

5 0

3 years ago

Read 2 more answers

Plss help asap im on a time limit

lys-0071 [83]

Answer: the first one

Step-by-step explanation: just trust me ;)

6 0

3 years ago

Read 2 more answers

A recipe calls for 6.67 cups of sugar, but Jake only has 1.8 cups. How much

Talja [164]

Answer:

Jake need 5.59 cup of sugar

3 0

3 years ago

For some particular website, the password must start with one of the letters W, X, Y, or Z. Then there must be 5 more charaters,

k0ka [10]

241,864,704 many different passwords are possible.

The total characters of the password is six in which it is given that first character should start with W, X, Y or Z. So the first character can be filled in 4 ways.

For next five characters it can be any letter of the alphabet or any numeric digit so it will be 26 + 10 = 36.

So second, third, fourth, fifth and sixth space can be taken by 36 characters.

Therefore the total no. of passwords will be 4 * 36 * 36 * 36 * 36 * 36 that is equal to 241,864,704.

To solve more questions like this

brainly.com/question/14767366

#SPJ1

3 0

1 year ago

The National Assessment of Educational Progress (NAEP) gives a math assessment every year to 12th graders in the U.S. On the mat

amid [387]

Answer:

The correct answer is option 2.

Step-by-step explanation:

In this case we need to test whether young men nationwide have a mean score below 275 in the National Assessment of Educational Progress math assessment.

The hypothesis is defined as follows:

H₀: μ = 275 vs. Hₐ: μ < 275

The significance level of the test is α = 0.05.

The p-value of the test is computed as, p-value = 0.20.

Decision rule:

A small p-value (typically ≤ 0.05) specifies solid proof against the null hypothesis (H₀), so you discard the null hypothesis.

A large p-value (> 0.05) specifies fragile proof against the null hypothesis, so you fail to discard the null hypothesis.

p-value = 0.20 > α = 0.05.

The null hypothesis was failed to rejected at 5% level of significance.

Thus, it can be concluded that there is not enough evidence to conclude that the mean score is less than 275 for young men nationwide.

Thus, the correct answer is option 2.

5 0

3 years ago