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Elenna [48]
3 years ago
13

Ice cubes,icicles,snowflakes, and glaciers are water in..

Physics
2 answers:
IRISSAK [1]3 years ago
8 0
Those are in a solid state.
s344n2d4d5 [400]3 years ago
4 0
Cities with colder climates such as Atlanta, Antarctica etc...
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PLEASE HELP!!! GIVING BRAINLIEST!! ill also answer questions that you have posted if you answer this correctly!!!! (40pts)
Soloha48 [4]

Answer:

Newton's second law: F=ma.

Force = mass x acceleration

This basically means, that the more massive something is, and the faster it is going, the more force the object will have.

So, the factors that can be used to find acceleration are:

F=ma

a=F/m

So, we see that the correct answer is A, mass and force.

Let me know if this helps!

8 0
2 years ago
Describe characteristics and identify oxidation-reduction(redox) reactions. <br><br> plz and thx
mars1129 [50]

Answer:

I hope This helps

Explanation:

The majority of oxidation-reduction (redox) reactions share two critical features. One is that a reduction happens in both, while equivalent oxidation occurs; they are combined.

8 0
2 years ago
Suppose a 1500 kg speed boat is traveling with a velocity of 30 m/s what is the speed boats Monument
DanielleElmas [232]

Answer: 45000kgm/s

Explanation:

Given that:

Mass of speed boat = 1500 kg

Velocity of speedboat = 30 m/s

Speed boats Momentum = ?

The Speed boat momentum is the product of its mass and the velocity by which it moves. Momentum is a vector quantity and measured in kgm/s

i.e Momentum = mass x velocity

= 1500 kg x 30 m/s

= 45000kgm/s

Thus, the speed boats momentum is 45000kgm/s

7 0
3 years ago
During a goal-line stand, a 112-kg fullback moving eastward with a speed of 6 m/s
11111nata11111 [884]

Answer:

-1.24 m/s

Explanation:

Total momentum before collision = total momentum after collision

Total momentum before collision = (mass of full back * velocity of fullback) + (mass of lineman * velocity of line man).

Mass of full back = 112 kg, mass of line bag = 120 kg, velocity of full back  6 m/s (east), velocity of line back = -8 m/s (west). Hence:

Total momentum before collision = (112 * 6) + (120 * -8) = 672 - 960 = -288 kgm/s

The total momentum after collision = (mass of full back + mass of line back) * velocity after collision.

Let velocity after collision be v, hence:

The total momentum after collision = (112 + 120)v = 232v

Total momentum before collision = total momentum after collision

-288 = 232v

v = -288 / 232

v = -1.24 m/s

Therefore after collision, the two players would move at a velocity 1.24 m/s west (the same direction as the lineman).

7 0
3 years ago
If someone is whispering, but you cant hear them, how do you fix that problem?
Readme [11.4K]
The answer is C
Hope this helps!
6 0
3 years ago
Read 2 more answers
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