Answer:
10000N
Explanation:
Given parameters:
Mass of the car = 1000kg
Acceleration = 3m/s²
g = 10m/s²
Unknown:
Weight of the car = ?
Solution:
To solve this problem we must understand that weight is the vertical gravitational force that acts on a body.
Weight = mass x acceleration due to gravity
So;
Weight = 1000 x 10 = 10000N
Answer:
a)
v = 14.1028 m/s
∅ = 83.0765° north of east
b)
the required distance is 40.98 m
Explanation:
Given that;
velocity of the river u = 1.70 m/s
velocity of boat v = 14.0 m/s
Now to get the velocity of the boat relative to shore;
( north of east), we say
a² + b² = c²
(1.70)² + (14.0)² = c²
2.89 + 196 = c²
198.89 = c²
c = √198.89
c = 14.1028 m/s
tan∅ = v/u = 14 / 1.7 = 8.23529
∅ = tan⁻¹ ( 8.23529 ) = 83.0765° north of east
Therefore, the velocity of the boat relative to shore is;
v = 14.1028 m/s
∅ = 83.0765° north of east
b)
width of river = 340 m,
ow far downstream has the boat moved by the time it reaches the north shore in meters = ?
we say;
340sin( 90° - 83.0765°)
⇒ 340sin( 6.9235°)
= 40.98 m
Therefore, the required distance is 40.98 m
<h3><u>Question: </u></h3>
The equation for the speed of a satellite in a circular orbit around the Earth depends on mass. Which mass?
a. The mass of the sun
b. The mass of the satellite
c. The mass of the Earth
<h3><u>Answer:</u></h3>
The equation for the speed of a satellite orbiting in a circular path around the earth depends upon the mass of Earth.
Option c
<h3><u>
Explanation:
</u></h3>
Any particular body performing circular motion has a centripetal force in picture. In this case of a satellite revolving in a circular orbit around the earth, the necessary centripetal force is provided by the gravitational force between the satellite and earth. Hence
.
Gravitational force between Earth and Satellite: ![F_{G} = \frac{G \times M_e \times M_s}{R^2}](https://tex.z-dn.net/?f=F_%7BG%7D%20%3D%20%5Cfrac%7BG%20%5Ctimes%20M_e%20%5Ctimes%20M_s%7D%7BR%5E2%7D)
Centripetal force of Satellite :![F_C = \frac{M_s \times V^2}{R}](https://tex.z-dn.net/?f=F_C%20%3D%20%5Cfrac%7BM_s%20%5Ctimes%20V%5E2%7D%7BR%7D)
Where G = Gravitational Constant
= Mass of Earth
= Mass of satellite
R= Radius of satellite’s circular orbit
V = Speed of satellite
Equating
, we get
Speed of Satellite ![V =\frac{\sqrt{G \times M_e}}{R}](https://tex.z-dn.net/?f=V%20%3D%5Cfrac%7B%5Csqrt%7BG%20%5Ctimes%20M_e%7D%7D%7BR%7D)
Thus the speed of satellite depends only on the mass of Earth.
Answer:
1.1 m/s²
Explanation:
From the question,
F -mgμ = ma.................... Equation 1
Where F = applied force, m = mass of the apple cart, g = acceleration due to gravity, μ = coefficient of friction., a = acceleration of the apple cart.
Given: F = 115 N, m = 25 kg, μ = 0.35
Constant: g = 10 m/s²
Substitute these values into equation 2
115-(25×10×0.35) = 25×a
115-87.5 = 25a
25a = 27.5
a = 27.5/25
a = 1.1 m/s²
Answer:
150 million kilometres
Explanation:
The astronomical unit (symbol: au, or AU or AU) is a unit of length, roughly the distance from Earth to the Sun and equal to 150 million kilometres (93 million miles) or 8.3 light minutes.