We will calculate it like this, We will make a right angle triangle by adding one new point called O for example, and O is located right under the point C, and on the right side of point D, so the coordinated for this point are O (8, -2). From there, length CD is calculated using the Pythagorean theorem, because we know that the CO = 4 and DO = 4, so:
CD^2 = CO^2 + DO^2
CD^2 = 4^2 + 4^2
DC^2 = 16 + 16
DC^2 = 32
DC = square root of 32 = square root of 16 * square root of 2
DC = 4 * square root of 2
The correct answer is B. 4*square root of 2.
Answer:
Explanation:
Simplify both sides of inequality
-2 / 3 > 1 / 5 z
Flip equation
1 / 5 z < -2 / 3
Multiply both sides by 5
(1 / 5 z) 5 < (-2 / 3) 5
Z < -10 / 3
20
Step-by-step explanation:
Step 1:
Let the number be 50 and to find 40% of 50 is given interms of expression as follows
To express the percentage the following strategy is used
Eg: 40% = 
∴ To express 40% of 50 is
Step 2:
On simplification the above expression we could get
= 20
Answer:
m∠W = 134
Step-by-step explanation:
JGN is congruent to AIW and the names of the triangles are both in the same order. That may sound confusing but this means that:
J = A
G = I
N = W
So, if angle N is 134 then angle W is the same.
Answer:
A: 82.5
Step-by-step explanation:
Average score of the 4 regular tests = (78 + 72 + 74 + 88)/4 = 78
We are told;
- the regular tests account for 40% of the final grade.
- final exam counts for 20%
- project counts for 10%
- homework counts for 30%
Thus;
weighted mean grade = (40% × 78) + (20% × 79) + (10% × 88) + (30% × 89) = 82.5
