What is the domain of the graph ?

Please help me asap

77julia77 [94]

Answer:

1929r9fij1j2jed8f82u2hfisj

Step-by-step explanation:

ieeidicicic8 iccuddeiwiweiod

5 0

3 years ago

Someone help me with these questions please

Kobotan [32]

To multiply mix numbers and a normal fractions you make the mix number into a improper fraction. To do that you multiply the bottom and add the top. Here are the answers:
1/2 x 5 1/2 = 2 3/4
3 3/4 x 1/2 = 1 7/8
1/2 x 3 1/3 = 1 1/6
3/4 x 3 1/6 = 3 1/8
2/1 x 1 1/7 = 2 2/3

4 0

3 years ago

A research group is curious about their city’s participation in flu shot clinics. They suspect that there is a difference betwee

Kipish [7]

Answer:

$t=\frac{(162-156)-0}{\sqrt{\frac{41^2}{22}+\frac{36^2}{20}}}}=0.505$

$p_v =2*P(t_{40}>0.505)=0.61633$

Comparing the p value with the significance level $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, then the difference between the two groups is NOT significantly different.

Step-by-step explanation:

Data given and notation

$\bar X_{1}=162$ represent the mean for sample of clinic attendees

$\bar X_{2}=156$ represent the mean for the sister city

$s_{1}=41$ represent the sample standard deviation for 1

$s_{2}=36$ represent the sample standard deviation for 2

$n_{1}=22$ sample size for the group 2

$n_{2}=20$ sample size for the group 2

$\alpha=0.05$ Significance level provided

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the difference in the population means, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}=0$

Alternative hypothesis: $\mu_{1} - \mu_{2}\neq 0$

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=22+20-2=40$

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:

$t=\frac{(162-156)-0}{\sqrt{\frac{41^2}{22}+\frac{36^2}{20}}}}=0.505$

P value

Since is a bilateral test the p value would be:

$p_v =2*P(t_{40}>0.505)=0.61633$

Comparing the p value with the significance level $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, then the difference between the two groups is NOT significantly different.

3 0

3 years ago

Identify the relation that is also a function. A. {(-1, 1) (0, 0) (1, 1) (2, 4)} B. {(3, 4) (2, 3) (3, 6) (2, 0)} C. {(1, 0) (2,

madreJ [45]

Answer:

Step-by-step explanation:

We are given four sets of relations as

$A. {(-1, 1) (0, 0) (1, 1) (2, 4)} \\B. {(3, 4) (2, 3) (3, 6) (2, 0)} \\C. {(1, 0) (2, 3) (3, -2) (1, 6)} \\D. {(3, 2) (3, -2) (3, 6) (3, 8)}$

A function is a relation in which every element in the first set has a unique image in the second set.

Let us check this aspect to A.

This is a function

Now come to B. 3 has two images 4 and 6. so not a function

Next is C. in C 1 has two images 0 and 6. So not a function

For D, 3 has 4 images so not a function.

3 0

3 years ago

What is the midpoint of a segment whose end points are (6,8) and (9,7)

SOVA2 [1]

Step-by-step explanation:

Midpoint = 1/2(6+9,8+7)

= 1/2(15,15) = (15/2,15/2)

5 0

3 years ago