166.4 g Ag grams of silver can be produced from 49.1 g of copper.
<h3>What is a mole?</h3>
A mole is a very important unit of measurement that chemists use. A mole of something means you have 602,214,076,000,000,000,000,000 of that thing, like how having a dozen eggs means you have twelve eggs.
→ 
63.55 g Cu —> 2 x 107.688 g Ag
63.55 g Cu gives 215.376 g of Ag
So, 49.1 g Cu —> 
= 166.4 g Ag
Hence, 166.4 g Ag grams of silver can be produced from 49.1 g of copper.
Learn more about moles here:
brainly.com/question/26416088
#SPJ1
Answer:
1.07 g
Explanation:
Half-life of Pu-234 = 4.98 hours
Initially present = 45 g
mass remains after 27 hours = ?
Solution:
Formula
mass remains = 1/ 2ⁿ (original mass) ……… (1)
Where “n” is the number of half lives
To find "n" for 27 hours
n = time passed / half-life . . . . . . . .(2)
put values in equation 2
n = 27 hr / 4.98 hr
n = 5.4
Mass after 27 hr
Put values in equation 1
mass remains = 1/ 2ⁿ (original mass)
mass remains = 1/ 2^5.4 (45 g)
mass remains = 1/ 42.2 (45 g)
mass remains = 0.0237 x 45 g
mass remains = 1.07 g
Answer:
n don't hv symmetry lines.
so the symmetry of n is 0
The number of beats the person have in 1.7 years is 6.7 x 10⁷ beats.
<h3>
Number of beats of the person</h3>
The number of beats of the person is calculated as follows;
n = bt
where;
- b is the beat rate
- n is number of beats
- t is time or duration
b = 75 beats/min
t = 1.7 years = 893520 mins
n = 75 beats/min x 893520 mins
n = 67,014,000
n = 6.7 x 10⁷ beats
Thus, the number of beats the person have in 1.7 years is 6.7 x 10⁷ beats.
Learn more about number of beats here: brainly.com/question/28245460
#SPJ1
Answer: pH = 4.996
Explanation:
No of moles = molarity x volume
:• no of moles of CH3COOH = 0.1M x 0.1L
n(CH3COOH) = 0.1mol
Since 0.03mole of NaOH is added, then 0.03 mole of CH3COOH will be converted to the conjugate.
Therefore, Moles of CH3COOH becomes,
0.1 - 0.03 = 0.07 mol
Subsequently, the moles of CH3COONa increases and becomes,
0.08 + 0.03 = 0.11 mol
Using the Hendersom-Hasselbach equation,
pH = pKa + log [Moles of conjugate÷ moles of Ch3COOH]
From literature, pKa of Ch3COOH is 4.8
Thus,
pH = 4.8 + log [0.11/0.07]
pH = 4.8 + 0.1963
pH = 4.996