<u>Answer:</u> The osmotic pressure is 54307.94 Torr.
<u>Explanation:</u>
To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

where,
= osmotic pressure of the solution = ?
i = Van't hoff factor = 3
C = concentration of solute = 0.958 M
R = Gas constant = 
T = temperature of the solution = ![30^oC=[30+273]K=303K](https://tex.z-dn.net/?f=30%5EoC%3D%5B30%2B273%5DK%3D303K)
Putting values in above equation, we get:

Hence, the osmotic pressure is 54307.94 Torr.
If 1000 ml (1 L) of CH₃COOH contain 1.25 mol
let 250 ml of CH₃COOH contain x
⇒ x =
= 0.3125 mol
∴ moles of CH₃COOH in 250ml is 0.3125 mol
Now, Mass = mole × molar mass
= 0.3125 mol × [(12 × 2)+(16 × 2)+(1 × 4)] g/mol
= 18.75 g
∴ Mass of CH₃COOH present in a 250 mL cup of 1.25 mol/L solution of vinegar is <span>18.75 g</span>
Co= 59g
S=32g
59+32=91g/mol
Answer:
All are correct
Explanation:
This might be a little deceptive. The question shows H, O and N which would designate ELEMENTS.
However, all of these can also be considered compounds and molecules as well. BUT, they are H₂, O₂ and N₂ when they are molecules and compounds.
So it depends on the whether the question is being literal or not.