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nignag [31]
2 years ago
9

In the following reaction, how many grams of silver can be produced from 49.1 g copper?

Chemistry
1 answer:
notsponge [240]2 years ago
5 0

166.4 g Ag grams of silver can be produced from 49.1 g of copper.

<h3>What is a mole?</h3>

A mole is a very important unit of measurement that chemists use. A mole of something means you have 602,214,076,000,000,000,000,000 of that thing, like how having a dozen eggs means you have twelve eggs.

1 mol Cu + 2 mol AgNO_3 → 2 mol Ag + 1 mol Cu(NO3)2

63.55 g Cu —> 2 x 107.688 g Ag

63.55 g Cu gives 215.376 g of Ag

So, 49.1 g Cu —> \frac{215.376 g X 49.1 g}{63.55 g}

= 166.4 g Ag

Hence, 166.4 g Ag grams of silver can be produced from 49.1 g of copper.

Learn more about moles here:

brainly.com/question/26416088

#SPJ1

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Name any two artificial elements.​
romanna [79]

Answer:

1) Hydrogen and Helium

I hope it will help you

6 0
2 years ago
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flammability is a material s ability to burn in the presence of a. hydrogen. b. nitrogen. c. oxygen. d. carbon dioxide.
WARRIOR [948]
I'm guessing it's C-Oxygen because in order to burn something, or create fire, oxygen HAS to be present.
4 0
3 years ago
A tank with volume of 2.4 cu ft is filled with Methane to a pressure of 1500 psia at 104 degrees F. Determine the molecular weig
Soloha48 [4]

Explanation:

It is known that equation for ideal gas is as follows.

               PV = nRT

The given data is as follows.

     Pressure, P = 1500 psia,     Temperature, T = 104^{o}F = 104 + 460 = 564 R

     Volume, V = 2.4 cubic ft,      R = 10.73 psia ft^{3}/lb mol R

Also, we know that number of moles is equal to mass divided by molar mass of the gas.

                n = \frac{mass}{\text{molar mass}}

            m = n \times W

                = 0.594 \times 16.04

                = 9.54 lb

Hence, molecular weight of the gas is 9.54 lb.

  • We will calculate the density as follows.

                d = \frac{PM}{RT}

                    = \frac{1500 \times 16.04}{10.73 \times 564}

                    = 3.975 lb/ft^{3}

  • Now, calculate the specific gravity of the gas as follows.

  Specific gravity relative to air = \frac{\text{density of methane}}{\text{density of air}}

                         = \frac{3.975 lb/ft^{3}}{0.0765 lb/ft^{3}}

                         = 51.96

6 0
3 years ago
Please assist me with chemistry assessment
Lera25 [3.4K]

Answer:

I don't know

Explanation:

7 0
1 year ago
0.00000000082 -<br> scientific notation
Nadusha1986 [10]

Answer:

8.2 x 106^-11

Explanation:

To begin this problem you must remember the basic rule of scientific notation, which is, must be between 1-10. .000000000082 is much smaller than 1. However by moving the decimal 11 spots to the right, we can make it 8.2

Continue to move the decimal to the right until the value is in the 1-10 range. Make sure to count the moves to the right.

Once the decimal is in the right spot count the spots moved.

Since the number is wayyy smaller than the answer given the number will be negative 10^-11, in order to make it what is was before.

6 0
3 years ago
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