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AleksAgata [21]
3 years ago
7

Keera decided to investigate how the growth of plants is affected by the time of day it is watered. She placed an equal amount o

f potting soil in three identical pots and planted three bean plants in each pot. The pots were placed on the same table so that they received the same amount of light. One pot was watered at sunrise, one at noon, and the last pot at sunset. After ten days, the height of each individual plant was measured and recorded. What is the independent variable in this investigation?
Chemistry
1 answer:
Arada [10]3 years ago
7 0
The time of day the plants are watered is the independent variable. Keera did everything else the same for each plant.
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sergeinik [125]
My answer is A. I'm probably wrong. in bad in this subject
7 0
3 years ago
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The density of lead is 11.4g/cm3. What volume, in ft3, would be occupied by 10.0 g of lead?
yawa3891 [41]

Answer:

3.10×10¯⁵ ft³.

Explanation:

The following data were obtained from the question:

Density (D) of lead = 11.4 g/cm³

Mass (m) of lead = 10 g

Volume (V) of lead =.?

Density (D) = mass (m) / Volume (V)

D = m/V

11.4 = 10 / V

Cross multiply

11.4 × V = 10

Divide both side by 11.4

V = 10 / 11.4

V = 0.877 cm³

Finally, we shall convert 0.877 cm³ to ft³. This can be obtained as follow:

1 cm³ = 3.531×10¯⁵ ft³

Therefore,

0.877 cm³ = 0.877 cm³ × 3.531×10¯⁵ ft³ /1 cm³

0.877 cm³ = 3.10×10¯⁵ ft³

Thus, 0.877 cm³ is equivalent to 3.10×10¯⁵ ft³.

Therefore, the volume of the lead in ft³ is 3.10×10¯⁵ ft³.

7 0
3 years ago
A 4.27 g sample of a lab solution contains 1.81g of acid. What is the concentration of the solution as a mass percentage?
vaieri [72.5K]

Answer:

42.38875878%

Explanation:

i divided 4.27 g from 1.81g using a percentage calculator but im not sure if its correct

5 0
2 years ago
Determine the molecular formula of a compound with an empirical formula of NH2 and a formula mass of 32.06 amu
Lilit [14]
N2H4

<span>Each nitrogen weighs 14.01 and each H weighs 1.01. !4.01+14.01+1.01+1.01 = 32.06 (roughly) </span>

4 0
3 years ago
Read 2 more answers
Glycerol has a molar mass of 92.09g/mol. Its percent composition is: 39.12% C, 8.75% H,
Sphinxa [80]

Answer:

Molecular formula => C₃H₈O₃

Explanation:

From the question given above, the following data were obtained:

Carbon (C) = 39.12%

Hydrogen (H) = 8.75%

Oxygen (O) = 51.12%

Molar mass of compound = 92.09 g/mol

Molecular formula =?

Next, we shall determine the empirical formula of the compound. This can be obtained as follow:

C = 39.12%

H = 8.75%

O = 51.12%

Divide by their molar mass

C = 39.12 / 12 = 3.26

H = 8.75 / 1 = 8.75

O = 51.12 / 16 = 3.195

Divide by the smallest

C = 3.26 / 3.195 = 1

H = 8.75 / 3.195 = 2.7

O = 3.195 / 3.195 = 1

Thus, the empirical formula is CH₂.₇O

Finally, we shall determine the molecular formula of the compound. This can be obtained as follow:

Empirical formula = CH₂.₇O

Molar mass of compound = 92.09 g/mol

Molecular formula =?

Molecular formula = Empirical formula × n

Molecular formula = [CH₂.₇O]ₙ

92.09 = [12 + (2.7×1) + 16] × n

92.09 = 30.7n

Divide both side by 30.7

n = 92.09 / 30.7

n = 3

Molecular formula = [CH₂.₇O]ₙ

Molecular formula = [CH₂.₇O]₃

Molecular formula = C₃H₈O₃

3 0
3 years ago
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