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Vera_Pavlovna [14]
4 years ago
7

Prove that the acceleration due to gravity is independent tothe mass of the falling body​

Physics
1 answer:
ra1l [238]4 years ago
4 0

Answer:

The force of gravity on an object increases with its mass; thus, the acceleration of gravity is constant.

Explanation:

one can prove this by plugging in values to Newton's 2nd law equation

F = ma, or by using the formula to calculate the force of gravity.

Force of Gravity = GMm/r^2

with G being the gravitational constant, M the mass of the earth, m the mass of the falling body, and r the distance from the earth's center.

Force of Gravity can be written as mg, with g being the acceleration due to gravity.

As we can see, m cancels on both sides, leaving

g = GM/r^2

Generally in physics problems, r will be treated as constant to achieve

g = 9.8m/s^2

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Your electric drill rotates initially at 5.21 rad/s. You slide the speed control and cause the drill to undergo constant angular
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Answer:

The drill's angular displacement during that time interval is 24.17 rad.

Explanation:

Given;

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The angular displacement of the electric drill at the given time interval is calculated as;

\theta = \omega _i t \ + \ \frac{1}{2}\alpha t^2\\\\\theta = (5.21 \ \times \ 4.13) \ + \ \frac{1}{2}(0.311)(4.13)^2\\\\\theta = (21.5173 ) \ + \ (2.6524)\\\\\theta =24.17 \ rad

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3 years ago
The weight of a hydraulic barber's chair with a client is 2100 N. When the barber steps on the input piston with a force of 44 N
guajiro [1.7K]

Answer:

\frac{r_1}{r_2}=6.9

Explanation:

According to Pascal's Law, the pressure transmitted from input pedal to the output plunger must be same:

P_1 = P_2\\\\\frac{F_1}{A_1}=\frac{F_2}{A_2}\\\\\frac{F_1}{F_2}=\frac{A_1}{A_2}\\\\\frac{F_1}{F_2}=\frac{\pi r_1^2}{\pi r_2^2}\\\\\frac{F_1}{F_2}=\frac{r_1^2}{r_2^2}

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r₁ = radius of output plunger

r₂ = radius of input piston

Therefore,

\frac{r_1^2}{r_2^2}=\frac{2100\ N}{44\ N}\\\\\frac{r_1}{r_2}=\sqrt{\frac{2100\ N}{44\ N}} \\\\\frac{r_1}{r_2}=6.9

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