Answer:
R₂ / R₁ = D / L
Explanation:
The resistance of a metal is
R = ρ L / A
Where ρ is the resistivity of aluminum, L is the length of the resistance and A its cross section
We apply this formal to both configurations
Small face measurements (W W)
The length is
L = W
Area
A = W W = W²
R₁ = ρ W / W² = ρ / W
Large face measurements (D L)
Length L = D= 2W
Area A = W L
R₂ = ρ D / WL = ρ 2W / W L = 2 ρ/L
The relationship is
R₂ / R₁ = 2W²/L
Well, first of all, the car is not moving at a uniform velocity, because,
on a curved path, its direction is constantly changing. Its speed may
be constant, but its velocity isn't.
The centripetal force on a mass 'm' that keeps it on a circle with radius 'r' is
F = (mass) · (speed)² / (radius).
For this particular car, the force is
(2,000 kg) · (25 m/s)² / (80 m)
= (2,000 kg) · (625 m²/s²) / (80 m)
= (2,000 · 625 / 80) (kg · m / s²)
= 15,625 newtons .
Answer:
(a) 0.017m/s^2
(b) 17/100,000
(c) 0.17m, 0.558ft
Explanation:
(a) speed = 60mph = 60m/1h × 1h/3600s = 0.017m/s, time = 10s
Acceleration (a) = speed ÷ time = 0.017m/s ÷ 10s = 0.0017m/s^2
(b) g = 9.8m/s^2, a = 0.0017m/s^2
a/g = 0.0017/9.8 = 0.00017 = 17/100,000
(c) Distance = speed × time = 0.017m/s × 10s = 0.17m
Distance in foot = 0.17 × 3.2808ft = 0.558ft
What if when I find my product, I get the same compound as I did in my
reactant? For example, FeCl3 + HCl ->FeCl3 + HCl. Then something is
wrong. In this case, FeCl3 and HCl usually don't react. In very
concentrated solutions of HCl, the FeCl4^- or FeCl6^-3 ion can form.
In... There you go my friend
Total energy =kinetic energy +potential energy
Change in energy =change in (kinetic energy +potential energy)
potential energy, 
where m is the mass, g is acceleration due to gravity and h is the height.
potential energy per unit mass =gh
change in potential energy per unit mass = 
where, h is the height.
kinetic energy= 
change in kinetic energy per unit mass,
In the given question:
Height varies from 90 m to zero as river flows from 90 m height to lake at 0 m
Velocity varies from 3m/s at top to o m/s at bottom.
Therefore,

Here, it was mentioned in the question internal energy of the water is constant and there is no change in the pressure at the inlet and outlet.