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3 years ago

What if we all jumped at the same time?

1 answer:

6 0

Technically, this delivers a lot of energy into the Earth, but it’s spread out over a large enough area that it doesn’t do much more than leave footprints in a lot of gardens. A slight pulse of pressure spreads through the North American continental crust and dissipates with little effect. The sound of all those feet hitting the ground creates a loud, drawn-out roar which lasts many seconds.

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A standard inverting op-amp circuit has an R1 of 10 kΩ and an Rf of 220 kΩ. If the offset current is 100 nA the output offset vo

kiruha [24]

Answer:

The value is $V_{os} = 0.001 \ V$

Explanation:

From the question we are told that

The circuit resistance is $R_1 = 10 \ k \Omega$

The feedback resistance is $R_f = 220 \ k \Omega$

The offset current is $I_{os } = 100 \ nA = 100 * 1)^{-9} \ A$

Generally the offset voltage is mathematically reparented as

$V_{os} = R_f * I_{os}$

=> $V_{os} = 10 *10^{3}* 100 *10^{-9}$

=> $V_{os} = 0.001 \ V$

6 0

3 years ago

E fundamental frequency of an open organ pipe corresponds to the middle c (261.6 hz on the chromatic musical scale). the third r

luda_lava [24]

The wavelength of the third resonance of the closed organ pipe is equal to the ratio between the speed of sound and the frequency of the 3rd harmonic:

$\lambda_3 = \frac{c}{f_3}=\frac{343 m/s}{261.6 Hz} =1.31 m$

The relationship between length of a closed pipe and wavelength of the standing waves inside is:

$L=\frac{n}{4}\lambda_n$

where n is the number of the harmonic. In this case, n=3, so the length of the pipe is

$L=\frac{3}{4}(1.31 m)=0.98 m$

8 0

3 years ago

What pressing problem did the invention of the cotton gin solve?

AlexFokin [52]

Are you answering a question or asking? You have already seemed to get the answer, A is the correct answer :I

4 0

3 years ago

What potential difference is needed to give a helium nucleus (q=2e) 85.0 kev of kinetic energy?

Vilka [71]

The kinetic energy K given to the helium nucleus is equal to its potential energy, which is
$E=q \Delta V$
where q=2e is the charge of the helium nucleus, and $\Delta V$ is the potential difference applied to it.
Since we know the kinetic energy, we have
$E=K=85~keV=q \Delta V$
and from this we can find the potential difference:
$\Delta V = \frac{K}{q}= \frac{85~keV}{2e}=42.5~kV$

6 0

3 years ago

A ladder 7.85 m long leans against the side of a building. If the ladder is inclined at an angle of 79.5° to the horizontal, wha

Slav-nsk [51]

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5 0

3 years ago