Answer:
The orbital speed of this second satellite is 5195.16 m/s.
Explanation:
Given that,
Orbital radius of first satellite 
Orbital radius of second satellite 
Mass of first satellite 
Mass of second satellite 
Orbital speed of first satellite = 4800 m/s
We need to calculate the orbital speed of this second satellite
Using formula of orbital speed

From this relation,

Now, 

Put the value into the formula


Hence, The orbital speed of this second satellite is 5195.16 m/s.
 
        
             
        
        
        
Answer:
0.8726  
Explanation:
We are to convert 1.85 x  
  to
 to 
First, let us convert the numerator from ft3 to m3
1 ft3 = 0.0283 m3
Hence, 
1.85 x  ft3 = 1.85 x
 ft3 = 1.85 x  x 0.0283 m3
 x 0.0283 m3
      = 52.355 m3
Now, let us convert the denominator from minutes to seconds
1 min = 60 sec
Therefore;
1.85 x  
  = 52.355/60
 = 52.355/60  
         = 0.8726  
 
        
             
        
        
        
Answer:

Explanation:
For the cat to stay in place on the merry go round without sliding the magnitude of maximum static friction must be equal to magnitude of centripetal force

Where the r is the radius of merry-go-round and v is the tangential speed
but

So we have

Substitute the given values
So

 
        
             
        
        
        
Answer:
Explanation:
When the number of slits increases, the intensity of fringes increases. 
So, the fringes appear to be more bright. 
As we know that the fringe width is inversely proportional to the number of slits, so as the number of slits increases, the fringe width decreases, hence the fringes are narrower, bright and close together.