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Shtirlitz [24]
2 years ago
5

Peter is a middle-aged, overweight man who is trying to decrease his body circumference. How could the serving size on a nutriti

on label help him lose weight?
Physics
1 answer:
gregori [183]2 years ago
3 0
One simple way to losing weight is by calorie counting. Peter can go to his nutritionist and learn just how much calories he can have as intake per day to lose weight. The nutrition label on any food item lists the calories and their serving sizes. This can be used to keep track of how much calories Peter has taken each day, so as to not go over his daily limit.
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A bullet is fired through a wooden board with a thickness of 9.0 cm. The bullet hits the board perpendicular to it, and with a s
gtnhenbr [62]

Answer:

-387883.3 m/s²

0.000286168546055 seconds

Explanation:

t = Time taken

u = Initial velocity = 370 m/s

v = Final velocity = 259 m/s

s = Displacement = 9 cm

a = Acceleration

v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{259^2-370^2}{2\times 9\times 10^{-2}}\\\Rightarrow a=-387883.3\ m/s^2

The acceleration of the bullet is -387883.3 m/s²

v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{259-370}{-387883.3}\\\Rightarrow t=0.000286168546055\ s

The time taken is 0.000286168546055 seconds

4 0
3 years ago
4) A satellite is in orbit around the earth. Which one feels the greater force?
tresset_1 [31]

Answer:

im pretty sure its D) ...

8 0
3 years ago
If a car is taveling with a speed 6 and comes to a curve in a flat road with radius ???? 13.5 m, what is the minumum value the c
Lemur [1.5K]

Answer:

\mu_s \geq 0.27

Explanation:

The centripetal force acting on the car must be equal to mv²/R, where m is the mass of the car, v its speed and R the radius of the curve. Since the only force acting on the car that is in the direction of the center of the circle is the frictional force, we have by the Newton's Second Law:

f_s=\frac{mv^{2}}{R}

But we know that:

f_s\leq \mu_s N

And the normal force is given by the sum of the forces in the vertical direction:

N-mg=0 \implies N=mg

Finally, we have:

f_s=\frac{mv^{2}}{R}  \leq \mu_s mg\\\\\implies \mu_s\geq \frac{v^{2}}{gR}  \\\\\mu_s\geq \frac{(6\frac{m}{s}) ^{2}}{(9.8\frac{m}{s^{2}})(13.5m) }\\\\\mu_s\geq0.27

So, the minimum value for the coefficient of friction is 0.27.

4 0
3 years ago
What will his final velocity be and how far will fall?
Pachacha [2.7K]

the final velocity will be 0

(v-u)=(0-0)

=0

3 0
3 years ago
Which of the following statements is true of scientific communication?
emmainna [20.7K]

Answer:  Many times, one investigation leads to another, with more questions, and more predictions.

Explanation: We never really know it all :)

6 0
1 year ago
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