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2 years ago

9

assuming that a Canadian $1.00 loonie is one inch wide, what would be the value in dollars if you had a row of loonies two and a

half miles long?

1 answer:

Natalka [10]2 years ago

6 0

The value would be $13200 because
1 mile = 5280 inches
5280 times 2 1/2 = 13200

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A textbook search committee is considering

lora16 [44]

Number of ways to select 3 books from 13 books for adoption is 286 .

<u>Step-by-step explanation:</u>

A Permutation is an ordered Combination. When the order does matter it is a Permutation. There are basically two types of permutation:

Repetition is Allowed: such as the lock above. It could be "333".

No Repetition: for example the first three people in a running race. You can't be first and second.

Formula is given by:

$nC_r= \frac{n!}{r! (n-r)!}$ , where n is the number of things to choose from, and we choose r of them, no repetitions, order matters. Here , n=13 , r=3.

⇒ $13C_3 = \frac{13!}{3!(13-3)!}$

⇒ $13C_3 = \frac{13!}{3!(10)!}$

⇒ $13C_3 = \frac{13(12)(11)10!}{3(2)(1)(10)!}$

⇒ $13C_3 = 13(2)(11)$

⇒ $13 C_3 = 286$

∴ Number of ways to select 3 books from 13 books for adoption is 286 .

3 0

2 years ago

Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)

viktelen [127]

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}$

The first line segment can be parameterized by $\mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle$ with $0\le t\le1$ . Denote this first segment by $C_1$ . Then

$\displaystyle\int_{C_1}\langle x+9y,x^2\rangle\cdot\mathbf dr_1=\int_{t=0}^{t=1}\langle9t+9t,81t^2\rangle\cdot\langle9,1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(162t+81t^2)\,\mathrm dt$
$=108$

The second line segment ( $C_2$ ) can be described by $\mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle$ , again with $0\le t\le1$ . Then

$\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(18-8t-(9+t)^2)\,\mathrm dt$
$=-\dfrac{229}3$

Finally,

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=108-\dfrac{229}3=\dfrac{95}3$

5 0

3 years ago

I need help with the questions

Naily [24]

Answer:

(-4,3) it is x axis -4 and y axis 3

8 0

2 years ago

Read 2 more answers

Dakota makes a salad dressing by combining 6 1/3 fluid ounces of oil and 3 3/8 fluid ounces of

pashok25 [27]

Answer:

6 11/24

Step-by-step explanation:

Do that on any calculator and it'll be that (also, if you have any other questions like that, I recommend MathPapa

7 0

2 years ago

The functions f (x) = 1/2x-3 and g(x) = -2x+ 2 intersect<br> at x = -2. True or false?

Norma-Jean [14]

9514 1404 393

Answer:

False

Step-by-step explanation:

f(-2) = (1/2)(-2) -3 = -1 -3 = -4

g(-2) = -2(-2) +2 = 4 +2 = 6

The function values are not the same at x=-2, so the graphs do not intersect there.

__

The graphs intersect at x=2.

4 0

2 years ago