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Triss [41]
3 years ago
9

a custodian pulls a vacuum 13.5 m with a 33.9 N force at a 55.0 degree angle , against a 14.2 N friction force . find the work d

one by the friction force
Physics
1 answer:
Elenna [48]3 years ago
4 0

Answer:

a. -191.7 J

Explanation:

The work done by a force is given by W = Fdcosθ where F = force applied and d = distance moved and θ is the angle between the force and distance moved.

Here, F = frictional force = 14.2 N

d = distance = 13.5 m

and θ = 180° since the direction of the frictional force and distance are opposite.

So, W = Fdcosθ = 14.2 × 13.5cos180° = -191.7 J

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Explain the benefits of understanding sound waves properties in real life.
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Answer:

The vibrations from sound waves cause our ears to send signals to our brains to create sound. The speed of sound waves will determine the sound's pitch, or how high or low something sounds. Sound waves are important because they allow us to hear important messages and emergency signals to protect ourselves.

Explanation:

I hope this helps :)

4 0
2 years ago
If you pull on something to the right with a force of 50 N and I pull on the same object to the left with a force of 60 N, what
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7 0
3 years ago
A 1.8 kg uniform rod with a length of 90 cm is attached at one end to a frictionless pivot. It is free to rotate about the pivot
Leokris [45]

Answer:

a. 32.67 rad/s²  b. 29.4 m/s²

Explanation:

a. The initial angular acceleration of the rod

Since torque τ = Iα = WL (since the weight of the rod W is the only force acting on the rod , so it gives it a torque, τ at distance L from the pivot )where I = rotational inertia of uniform rod about pivot = mL²/3 (moment of inertia about an axis through one end of the rod), α = initial angular acceleration, W = weight of rod = mg where m = mass of rod = 1.8 kg and g = acceleration due to gravity = 9.8 m/s² and L = length of rod = 90 cm = 0.9 m.

So, Iα = WL

mL²α/3 = mgL

dividing through by mL, we have

Lα/3 = g

multiplying both sides by 3, we have

Lα = 3g

dividing both sides by L, we have

α = 3g/L

Substituting the values of the variables, we have

α = 3g/L

= 3 × 9.8 m/s²/0.9 m

= 29.4/0.9 rad/s²

= 32.67 rad/s²

b. The initial linear acceleration of the right end of the rod?

The linear acceleration at the initial point is tangential, so a = Lα = 0.9 m × 32.67 rad/s² = 29.4 m/s²

5 0
3 years ago
•Would a moving fan have energy? Why or why not.
Pepsi [2]
Moving fan has rotational kinetic energy
Non moving fan has no energy since it is in rest
7 0
3 years ago
Which statement about projectile motion is true?
Svetllana [295]

C. The range of a projectile increases with an increase in the angle of launch.

3 0
3 years ago
Read 2 more answers
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