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4 years ago

The amoeba is a protozoan that moves with _____.

Physics

2 answers:

Rom4ik [11]4 years ago

6 0

The amoeba is a protozoan that moves with <span>pseudopodia.

Answer: P</span><span>seudopodia</span>

NISA [10]4 years ago

5 0

- - Pseudopodia

Why?

The amoeba that is a protozoan moves with Pseudopodia.

You might be interested in

To reduce inductive reactance, what devices are normally placed on transmission or distribution lines?

UkoKoshka [18]

Answer : Capacitors

Explanation : Capacitors are normally placed on transmission or distribution lines when to reduce inductive reactance.

This is because it enhances electromechanical and voltage stability , limit voltage dips at network nodes and reduces the power loss.

So, we can say that inductive reactance normally replace by the capacitors.

4 0

3 years ago

N in-ground swimming pool has the dimensions shown in the drawing. It is filled with water to a uniform depth of 3.00 m. The den

Doss [256]

Answer:

The pressure is $P = 1.31*10^{5} \ Pa$

Explanation:

From the question we are told that

The depth of the swimming pool is $d = 3.00 \ m$

The density of water is $\rho = 1.00*10^{3} \ kg /m^3$

Generally the total pressure exerted on the bottom of the swimming pool is mathematically represented as

$P = P_o + \rho * g * h$

Here $P_o$ is the atmospheric pressure with value

$P_o = 101325 \ Pa$

$P = 101325 + [1000 * 9.8 * 3]$

=> $P = 130725 \ Pa$

=> $P = 1.31*10^{5} \ Pa$

7 0

3 years ago

What is the mass of a soda can on a triple beam balance

Scrat [10]

It depends on the kind of soda can

6 0

3 years ago

What is the charge on an object that has 1.09x10^13 excess electrons?

Nadya [2.5K]

Answer:

$-1.74\cdot 10^{-6} C$

Explanation:

The electron is the particle that rotates around the nucleus of the atom; it has a negative electric charge equal to :

$e=-1.6\cdot 10^{-19}C$

which is known as fundamental charge.

For an object containing N excess electrons, the total charge of the object is

$Q=Ne$

In this problem, the number of excess electrons in the object is:

$N=1.09\cdot 10^{13}$

Therefore, by plugging it the numbers, we can find the value of Q, the total charge of the object:

$Q=(1.09\cdot 10^{13})(-1.6\cdot 10^{-19})=-1.74\cdot 10^{-6} C$

5 0

4 years ago

The electric potential ( relative to infinity ) due to a single point charge Q is 400 V at a point that is 0.6 m to the right of

UkoKoshka [18]

Answer:

The potential at a distance of 0.9 m is 266.67 V.

Explanation:

Charge = Q

Potential is 400 V at a distance 0.6 m .

Let the potential is V at a distance 0.9 m.

Use the formula of potential.

$V = \frac{Kq}{r}\\\\\frac{V}{400}=\frac{0.6}{0.9}\\\\V = 266.67 V$

5 0

3 years ago