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3 years ago

#4 If 6 +x= 13, then find the value of 8x - 31. A7 B) 17 C) 25 D) 73

Mathematics

2 answers:

amid [387]3 years ago

8 0

C. 25
6+x=13
x=7
8(7)-31=25

Paraphin [41]3 years ago

6 0

C. 25
6+x= 13
X=7
8(7)-31=25

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BRAINLIEST???PLEASE HELPPP!!!!!

Luden [163]

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3 years ago

Is 1000 a term in the sequence 50,65,80,95

Alex Ar [27]

Yes it is

it’s the 41st term

EXPLANATION:

the nth term would be 15n+35
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1. 2. 3. 4.
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2 years ago

Find an nth degree polynomial function with real coefficients satisfying the given conditions.

damaskus [11]

Step-by-step explanation:

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will be

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Since i is one root, it conjugate, must be the other.

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3 years ago

Find the volume of a pyramid with a square base, where the perimeter of the base is 7.3\text{ ft}7.3 ft and the height of the py

Cloud [144]

Answer:

$V=6.66\ ft^3$

Step-by-step explanation:

The perimeter of the square base of a pyramid = 7.3 ft

The height of the pyramid, h = 6ft

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P = 4s, s is the side of square

7.3 = 4s

s = 1.825 ft

The volume of a pyramid is given by :

$V=\dfrac{lbh}{3}$

Here, l = b = 1.825 ft

So,

$V=\dfrac{1.825\times 1.825\times 6}{3}\\\\V=6.66\ ft^3$

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3 years ago

Find the exact length of the midsegment of the trapezoid with the vertices S(−2, 4), T(−2,−4), U(3,−2), V(13, 10).

Vlada [557]

Check the picture below.

first off we'll need to know the midpoints of ST and UV, well, from ST as you can see in the picture, is just a vertical line, so its midpoint is simply (-2,0), let's find it for UV

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ U(\stackrel{x_1}{3}~,~\stackrel{y_1}{-2})\qquad V(\stackrel{x_2}{13}~,~\stackrel{y_2}{10}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{13+3}{2}~~,~~\cfrac{10-2}{2} \right)\implies \left( \cfrac{16}{2}~~,~~\cfrac{8}{2} \right)\implies (8~~,~~4) \\\\[-0.35em] ~\dotfill$

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-2}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{8}~,~\stackrel{y_2}{4})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d = \sqrt{[8-(-2)]^2+[4-0]^2}\implies d=\sqrt{(8+2)^2+(4-0)^2} \\\\\\ d=\sqrt{10^2+4^2}\implies d=\sqrt{116}\implies d\approx 10.77$

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3 years ago