Answer:
The current in the rods is 171.26 A.
Explanation:
Given that,
Length of rod = 0.85 m
Mass of rod = 0.073 kg
Distance
The rods carry the same current in the same direction.
We need to calculate the current
I is the current through each of the wires then the force per unit length on each of them is
Using formula of force
Where, m = mass of rod
l = length of rod
Put the value into the formula
Hence, The current in the rods is 171.26 A.
The change in the gravitational potential energy is represented by the equation
u = ΔPE = Δmgh
since the mass of the system will remain constant and the acceleration due to gravity will also remain constant, the equation will become
u = mg Δh
Answer:
2.6 N
Explanation:
Given:
v₀ = 0 m/s
v = 22 m/s
t = 22 s
Find: a
v = at + v₀
(22 m/s) = a (22 s) + (0 m/s)
a = 1 m/s²
Newton's second law:
F = ma
F = (2.6 kg) (1 m/s²)
F = 2.6 N
Answer:
592.92 x 10³ Pa
Explanation:
Mole of ammonia required = 10 g / 17 =0 .588 moles
We shall have to find pressure of .588 moles of ammonia at 30 degree having volume of 2.5 x 10⁻³ m³. We can calculate it as follows .
From the relation
PV = nRT
P x 2.5 x 10⁻³ = .588 x 8.32 x ( 273 + 30 )
P = 592.92 x 10³ Pa