Could you supply u with some answer choices please?
Answer:
The spring constant of the spring is 205.42 N/m.
Explanation:
Springs have their own natural "spring constants" that define how stiff they are. The letter k is used for the spring constant, and it has the units N/m.
k = -F/x
The period of a spring-mass system is proportional to the square root of the mass and inversely proportional to the square root of the spring constant.
Given:
mass of object in SHM = m = 0.30 kg
Time period of the spring mass system = 0.24s
Spring constant = k ?
Finding 'k' using Time period 'T':
We know that
Answer:
1.29 s
Explanation:
Given:
Δy = 1.40 m
v₀ = 0 m/s
a = 1.67 m/s²
Find: t
Δy = v₀ t + ½ at²
(1.40 m) = (0 m/s) t + ½ (1.67 m/s²) t²
t = 1.29 s
Answer:
Magnitude of Thickness has order of 2.919 × 
m
Explanation:
Thickness of book is 3.2 cm.
Number of pages in the book is 1096.
Thickness of 1096 pages is 3.2 cm.
Thus, thickness of 1 page is 
cm
Thickness of 1 page of book is 0.002919 cm
Magnitude of Thickness has order of 2.919 × m
Answer:
F = 1.2×10⁻³ N
Explanation:
From the question,
Applying newton's second law of motion,
F = m(v-u)/t................... Equation 1
Given: F = magnitude of the average force exerted on the ball, m = mass of the ball, v = final velocity, u = initial velocity, t = time of contact.
Note: let downward be negative and upward be positive.
Given: m = 48 g = 48/1000 = 0.048 kg, v = 17 m/s, u = -28 m/s (downward),
t = 1800 s
Substitute into equation 1
F = 0.048(17-[28])/1800
F = 1.2×10⁻³ N
