Answer: A) ![6.38(10)^{6} m](https://tex.z-dn.net/?f=6.38%2810%29%5E%7B6%7D%20m)
Explanation:
The equation for the moment of inertia
of a sphere is:
(1)
Where:
is the moment of inertia of the planet (assumed with the shape of a sphere)
is the mass of the planet
is the radius of the planet
Isolating
from (1):
(2)
Solving:
(3)
Finally:
Therefore, the correct option is A.
<span>For a point mass the moment of inertia is just
the mass times the square of perpendicular distance to the rotation axis, I =
mr^2. That point mass relationship becomes the basis for all other moments of
inertia since any object can be built up from a collection of point masses. So the
I = (1.2 kg)(0.66m/2)^2 = 0.1307 kg m2</span>
C, N and O all belong to the same period, in which it's 2nd Period.
I think it would be WEIGHT and ROUGHNESS OF SURFACE.