The standard form for an equation is y=mx+b. You find the slope by using the formula of rise over run. This means that for problem 6 you first look to see if its positive or negative slope. The slope is positive if the line is going uphill and if its going downhill its negative. The slope would be negative for number 6 because it is going downhill. Then for the actualy slope you would start with rise. So you look at the point (0,1) and go up 3 until you hit the line of the other point and run over 2. So your slope would be -3/2.
Answer:
y = (-3/2)x + 7
Step-by-step explanation:
3x + 2y = -4 (rearrange to slope intercept form y = mx + b)
2y = -3x - 4
y = (-3/2) x - 2
comparing this to the general form of a linear equation : y = mx + b
we see that slope of this line (and every line that is parallel to this line),
m = -3/2
if we sub this back in to the general form, we get:
y = (-3/2)x + b
We are still missing the value of b. To find this, we are given that the point (4,1) lies on the line. We simply substitute this back into the equation and solve for b.
1 = (-3/2)4 + b
1 = -6 + b
b = 7
substituting this back into the equation:
y = (-3/2)x + 7
Answer:
Step-by-step explanation:
16/20 = 48/60
960 = 960
Answer is C
Answer:
The Angle-Side-Angle Postulate (ASA) states that if two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the two triangles are congruent.
Step-by-step explanation:
