Answer:
[HCl] = 4.54 M
Explanation:
14.2 % by mass is 14.2 g in 100 g of solution.
Let's calculate the moles of our solute, HCl
14.2 g / 36.45 g/mol = 0.389 mol
Molarity is mol/L (moles of solute in 1L of solution)
Let's determine the volume of solution with density
Solution density = Solution mass / Solution volume
Solution volume = Solution mass / Solution density
Solution volume = 100 g / 1.1684 g/mL → 85.6 mL
For molarity, we need the volume in L. Let's make the unit change.
85.6 mL . 1 L/1000mL = 0.0856L
Molarity is 0.389 mol / 0.0856L → 4.54 M
Hey there!
Molar mass Na2SO4 = 142.04 g/mol
Number of moles:
n = m / mm
n = 25 / 142.04
n = 0.176 moles of Na2SO4
Therefore, use the Avogadro constant
1 mole Na2SO4 ------------------- 6.02x10²³ molecules
0.176 moles Na2SO4 ------------ molecules ??
0.176 x ( 6.02x10²³ ) / 1
=> 1.059x10²³ molecules of Na2SO4
hope this helps!
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Then you will multiply the number of moles by 6.022×1023formula units/mol . To determine the molar mass of a compound, add the atomic weight on the periodic table in g/mol times each element's subscript. Since the formula unit CaO has no subscripts, they are understood to be 1
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