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son4ous [18]
2 years ago
6

Hey! If someone could help me out I would really appreciate it even if it was just one answer. I'm really stuck on 3. Its second

year of chem!

Chemistry
1 answer:
Sphinxa [80]2 years ago
7 0

Answer:

I would go for number 5 . It sounds more logical to me.

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Science: Number 3 plsss
Tema [17]

Answer:

the plants it will be bigger if you take care it so much the plant it will help in our world

Explanation:

I HOPE ITS HELP<em>.</em><em>.</em><em>.</em><em>P</em><em>L</em><em>E</em><em>A</em><em>S</em><em>E</em><em> </em><em>C</em><em>O</em><em>R</em><em>R</em><em>E</em><em>C</em><em>T</em><em> </em><em>M</em><em>E</em><em> </em><em>I</em><em>F</em><em> </em><em>I</em><em>M</em><em> </em><em>W</em><em>R</em><em>O</em><em>N</em><em>G</em>

3 0
3 years ago
Read 2 more answers
1. Which of the following is a linear inequality in two variables?
Stolb23 [73]

Answer:

  1. A. 7x - 4y = 3
  2. C. 6p 2
  3. C. 2
  4. A. (4, 5)
3 0
3 years ago
Read 2 more answers
For the following reaction, 22.8 grams of diphosphorus pentoxide are allowed to react with 13.5 grams of water . diphosphorus pe
gavmur [86]

Answer:

m_{H_3PO_4}=31.5gH_3PO_4

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

P_2O_5(s)+3H_2O(l)\rightarrow 2H_3PO_4(aq)

Thus, since the diphosphorus pentoxide to water molar ratio is 1:3 and we are given the mass of both of them, for the calculation of the maximum mass phosphoric acid that is yielded, one could first identify the limiting reactant, for which we compute the available moles of diphosphorus pentoxide (molar mass 142 g/mol):

n_{P_2O_5}=22.8gP_2O_5*\frac{1molP_2O_5}{142gP_2O_5}=0.161molP_2O_5

And the moles of diphosphorus pentoxide that are consumed by 13.5 g of water (molar mass 18 g/mol):

n_{P_2O_5}^{consumed}=13.5gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{1molP_2O_5}{3molH_2O}  =0.25molP_2O_5

Hence, since less moles of diphosphorus pentoxide are available, we sum up it is the limiting reactant, therefore, the maximum mass of phosphoric acid (molar mass 98 g/mol) is computed by considering the 1:2 molar ratio between them as follows:

m_{H_3PO_4}=0.161molP_2O_5*\frac{2molH_3PO_4}{1molP_2O_5} *\frac{98gH_3PO_4}{1molH_3PO_4} \\\\m_{H_3PO_4}=31.5gH_3PO_4

Regards.

8 0
3 years ago
Arrange the elements in order of increasing ionization energy. Use the
UNO [17]

Answer:

Gallium, Phosphorus, Chlorine, Fluorine

Explanation:

Arrange the elements in order of increasing ionization energy. Use the periodic table to identify their positions on the table.

Drag each tile to the correct box.

Tiles

chlorinefluorinegalliumphosphorus

Sequence

5 0
3 years ago
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Is MgCO3 organic or inorganic
schepotkina [342]
Its inorganic as MgCO3 is contains no carbon more hydrogen which is a crutial component of all organic compounds 
4 0
3 years ago
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