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Darina [25.2K]
3 years ago
13

Which Greek mathematician is known as the Father of Geometry? A. Pythagoras B. Thales C. Euclid D. Hippocrates

Mathematics
1 answer:
Brrunno [24]3 years ago
8 0

Answer: C (Euclid is known as the Father of Geometry)



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Write a two-column proof. Given: line BD bisects angle CBE. Prove: angle ABD approximately equal to angle FBD.
ale4655 [162]

Answer:

The proof is derived from the summarily following equations;

∠FBE + ∠EBD = ∠CBA + ∠CBD

∠FBE + ∠EBD = ∠FBD

∠CBA + ∠CBD = ∠ABD

Therefore;

∠ABD ≅ ∠FBD

Step-by-step explanation:

The two column proof is given as follows;

Statement {}                                       Reason          

\underset{BD}{\rightarrow} bisects ∠CBE {}                            Given

Therefore;

∠EBD ≅ ∠CBD  {}                              Definition of angle bisector

∠FBE ≅ ∠CBA {}                                Vertically opposite angles are congruent

Therefore, we have;

∠FBE + ∠EBD = ∠CBA + ∠CBD {}     Transitive property

∠FBE + ∠EBD = ∠FBD {}                    Angle addition postulate

∠CBA + ∠CBD = ∠ABD {}                   Angle addition postulate

Therefore;

∠ABD ≅ ∠FBD        {}                          Transitive property.

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3 years ago
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jeyben [28]
1. Add 4x back into -2, you now have -4y=-4x-2. Add +4 from y and now you are at y=-4x+2 and this is the answer!

2. Add -9x back into -3, you now have -4y=9x-3. Add +4 from y and now you are at y=9x-7 and this is your answer!!

I hope this helped! Brainliest? :) -Raven❤️
7 0
3 years ago
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