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Andrew [12]
3 years ago
6

What is the difference in mesomeric and electromeric effect​

Chemistry
1 answer:
Leya [2.2K]3 years ago
8 0

Cause their are both have difference s

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Is sulfur a metal, nonmetal, metalloid, or noble gas?
Blababa [14]
Sulfer is a nonmetal
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2 years ago
A wooden artifact from a Chinese temple has a 14C activity of 42.8 counts per minute as compared with an activity of 58.2 counts
Arlecino [84]

Answer : The age of the artifact is, 2.54\times 10^3\text{ years}

Explanation :

Half-life = 5715 years

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{5715\text{ years}}

k=1.21\times 10^{-4}\text{ years}^{-1}

Now we have to calculate the time taken to decay.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant

t = time taken by sample = ?

a = initial activity of the reactant  = 58.2 counts per minute

a - x = activity left after decay process  = 42.8 counts per minute

Now put all the given values in above equation, we get

t=\frac{2.303}{1.21\times 10^{-4}}\log\frac{58.2}{42.8}

t=2540.5\text{ years}=2.54\times 10^3\text{ years}

Therefore, the age of the artifact is, 2.54\times 10^3\text{ years}

4 0
3 years ago
A physiologist is studying the homeostatic control of blood ph. What type of receptor might be responsible for detecting changes
sertanlavr [38]

Answer:

Chemoreceptors should be your answer :)

Explanation:

8 0
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Due today: <br> How do you think the birds "predicted" Hurricanes
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Research has shown that birds can hear infrasound (ref) and are sensitive to barometric pressure (ref and ref), so they know when a storm is on its way -- especially when the storm is as large and as powerful as a hurricane.Sep 8, 2017
8 0
2 years ago
RATE LAW QUESTION !
vivado [14]
In general, we have this rate law express.:

\mathrm{Rate} = k \cdot [A]^x [B]^y
we need to find x and y

ignore the given overall chemical reaction equation as we only preduct rate law from mechanism (not given to us).

then we go to compare two experiments in which only one concentration is changed

compare experiments 1 and 4 to find the effect of changing [B]
divide the larger [B] (experiment 4)  by the smaller [B] (experiment 1) and call it Δ[B]

Δ[B]= 0.3 / 0.1 = 3

now divide experiment 4 by experient 1 for the given reaction rates, calling it ΔRate:

ΔRate = 1.7 × 10⁻⁵ / 5.5 × 10⁻⁶ = 34/11 = 3.090909...

solve for y in the equation \Delta \mathrm{Rate} = \Delta [B]^y

3.09 = (3)^y \implies y \approx 1

To this point, \mathrm{Rate} = k \cdot [A]^x [B]^1

do the same to find x.
choose two experiments in which only the concentration of B is unchanged:

Dividing experiment 3 by experiment 2:
Δ[A] = 0.4 / 0.2 = 2
ΔRate = 8.8 × 10⁻⁵ / 2.2 × 10⁻⁵ = 4

solve for x for \Delta \mathrm{Rate} = \Delta [A]^x

4=  (2)^x \implies x = 2

the rate law is

Rate = k·[A]²[B]
6 0
3 years ago
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