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MariettaO [177]
3 years ago
6

The molarity of a solution that contains 14 g KOH per 150 mL of solution is:

Chemistry
2 answers:
Maksim231197 [3]3 years ago
6 0

Answer:

1.67 M

Explanation:

Molarity =  \frac{moles}{liter}

Moles = \frac{mass}{molar mass}

Given

Mass of KOH =  14 g

Molar mass of KOH =  56.1056 g/mol

Moles of KOH =  \frac{14 g}{56.1056 g/mol} = 0.25 mol

Volume of solution = 150 ml = 0.15 L (1 L = 1000 ml)

Molarity = \frac{0.25 mol}{0.15 L }= 1.67 M

lys-0071 [83]3 years ago
3 0
<span>The molarity of a solution that contains 14 g KOH per 150 mL of solution is 1.7 m</span>
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