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3 years ago

The molarity of a solution that contains 14 g KOH per 150 mL of solution is:

Chemistry

2 answers:

Maksim231197 [3]3 years ago

6 0

Answer:

1.67 M

Explanation:

Molarity = $\frac{moles}{liter}$

Moles = $\frac{mass}{molar mass}$

Given

Mass of KOH = 14 g

Molar mass of KOH = 56.1056 g/mol

Moles of KOH = $\frac{14 g}{56.1056 g/mol}$ = 0.25 mol

Volume of solution = 150 ml = 0.15 L (1 L = 1000 ml)

Molarity = $\frac{0.25 mol}{0.15 L }$ = 1.67 M

lys-0071 [83]3 years ago

3 0

<span>The molarity of a solution that contains 14 g KOH per 150 mL of solution is 1.7 m</span>

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