Question

The molarity of a solution that contains 14 g KOH per 150 mL of solution is:

Answer 1

Answer:

1.67 M

Explanation:

Molarity =  $\frac{moles}{liter}$

Moles = $\frac{mass}{molar mass}$

Given

Mass of KOH =  14 g

Molar mass of KOH =  56.1056 g/mol

Moles of KOH =  $\frac{14 g}{56.1056 g/mol}$ = 0.25 mol

Volume of solution = 150 ml = 0.15 L (1 L = 1000 ml)

Molarity = $\frac{0.25 mol}{0.15 L }$= 1.67 M

Answer 2

The molarity of a solution that contains 14 g KOH per 150 mL of solution is 1.7 m