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padilas [110]
3 years ago
5

What is the percent composition of NaCl? Show all work please

Chemistry
1 answer:
Amiraneli [1.4K]3 years ago
7 0

Answer:

NaCl = 58.44g/mol

Explanation:

Na = 22.99/58.44 × 100 = 39.33%

Cl = 35.45/58.44 × 100 = 60.66%

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Iam willing to play truth and dare

Explanation:

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The freezing point of diet soda is higher than the freezing point of regular soda, but lower than 0 degrees celcius, the freezin
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Answer:

Explanation:

Both Diet Soda and regular soda contain sweeteners.

When a solute is dissolved in solution, the solution undergoes *freezing point depression* it freezing point reduces. The magnitude of freezing point depression is directly proportional to the amount of solute in a solution.

Since soda Both regular or diet soda contains more solute than water , their freezing point is will consequently be lower than water

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3 years ago
A sample of a pure substance with a density of 3 g/mL is separated into two pieces. One piece has a mass of 50 g and the other p
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Answer:

8.3ml

Explanation:

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4 0
2 years ago
The vapor pressure of ethanol is 30°C at 98.5 mmHg and the heat of vaporization is 39.3 kJ/mol. Determine the normal boiling poi
Gelneren [198K]

Answer : The normal boiling point of ethanol will be, 348.67K or 75.67^oC

Explanation :

The Clausius- Clapeyron equation is :

\ln (\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}\times (\frac{1}{T_1}-\frac{1}{T_2})

where,

P_1 = vapor pressure of ethanol at 30^oC = 98.5 mmHg

P_2 = vapor pressure of ethanol at normal boiling point = 1 atm = 760 mmHg

T_1 = temperature of ethanol = 30^oC=273+30=303K

T_2 = normal boiling point of ethanol = ?

\Delta H_{vap} = heat of vaporization = 39.3 kJ/mole = 39300 J/mole

R = universal constant = 8.314 J/K.mole

Now put all the given values in the above formula, we get:

\ln (\frac{760mmHg}{98.5mmHg})=\frac{39300J/mole}{8.314J/K.mole}\times (\frac{1}{303K}-\frac{1}{T_2})

T_2=348.67K=348.67-273=75.67^oC

Hence, the normal boiling point of ethanol will be, 348.67K or 75.67^oC

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3 years ago
How many moles are in 1.20 x 10^21 atoms of Phosphorus?
Ludmilka [50]

Answer:

You would get 19.969 moles

Explanation:

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