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Katyanochek1 [597]
3 years ago
11

SOLVE

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
5 0

Answer:

26.4 is what i came up with if you divide im probably wrong sorry if i am

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Consider a game in which players roll a number cube to determine the number of points earned. If a player rolls a prime number,
Aleksandr-060686 [28]

Answer:

The expected value of the points earned on a single roll in this game is \dfrac{1}{6} = 0.1667 .

Step-by-step explanation:

We are given that consider a game in which players roll a number cube to determine the number of points earned. If a player rolls a prime number, that many points will be added to the player’s total. Any other roll will be deducted from the player’s total.

Assuming that the numbered cube is a dice with numbers (1, 2, 3, 4, 5, and 6).

Here, the prime numbers are = 1, 2, 3 and 5

Numbers which are not prime = 4 and 6

This means that if the dice got the number 1, 2, 3 or 5, then that many points will be added to the player’s total and if the dice got the number 4 or 6, then that many points will get deducted from the player’s total.

Here, we have to make a probability distribution to find the expected value of the points earned on a single roll in this game.

Note that the probability of getting any of the specific number on the dice is   \dfrac{1}{6} .

      Numbers on the dice (X)                       P(X)

                      +1                                                 \frac{1}{6}

                      +2                                                \frac{1}{6}

                      +3                                                \frac{1}{6}

                      -4                                                 \frac{1}{6}

                      +5                                                \frac{1}{6}

                      -6                                                 \frac{1}{6}

Here (+) sign represent the addition in the player's total and (-) sign represents the deduction in the player's total.

Now, the expected value of X, E(X)  =  \sum X \times P(X)

   =  (+1) \times \frac{1}{6} +(+2) \times \frac{1}{6} +(+3) \times \frac{1}{6} +(-4) \times \frac{1}{6} +(+5) \times \frac{1}{6} +(-6) \times \frac{1}{6}

   =  \frac{1}{6} + \frac{2}{6} + \frac{3}{6} - \frac{4}{6} + \frac{5}{6} - \frac{6}{6}

   =  \frac{1+2+3-4+5-6}{6}

   =  \frac{11-10}{6}= \frac{1}{6}

Hence, the expected value of the points earned on a single roll in this game is  \frac{1}{6} = 0.1667 .

4 0
3 years ago
If f(x) varies directly with x and f(x)=40 when x=8, find the value of f(x) when x=2.
melamori03 [73]

f(x)=40

x=8

so if x=2 it would be 40/8 which is 5

6 0
3 years ago
Read 2 more answers
Tent: If a function f has an inverse and f(-3) = 6, then f-1(6)
Dvinal [7]
I’m tryna look for that too
4 0
3 years ago
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What is f(-3) if f(x) = 12x + 1] + 5?<br><br> Α. 0<br><br> B. 10<br><br> C. 12<br><br> D. -10
alexgriva [62]
Use the given functions to set up and simplify
f
(
−
3
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f
(
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3 0
3 years ago
beginning at sea level a scuba diver dove 1 2/3 feet into the water , and then dove an additional 3 2/5 feet at what elevation i
skad [1K]

The given details are illustrations of addition and subtractions of fractions.  The scuba driver is at an elevation of -5\frac{1}{15} ft below the sea  level.

Given that:

n_1 = 1\frac 23 --- the first dive

n_2 = 3\frac 25 ---- the additional dive

From the question, we understand that the diver starts at the sea level.

This is represented with 0ft.

So, the diver's elevation (d) is calculated as follows:

d = 0 - n_1 - n_2 --- we use subtraction because the diver is below the sea level

So, we have:

d = 0 - 1\frac 23 - 3\frac 25

d = - 1\frac 23 - 3\frac 25

Convert fractions

d = - \frac 53 - \frac{17}5

Take LCM

d = \frac{-5 \times 5 - 17 \times 3}{15}

d = \frac{-76}{15}

Reduce fraction

d = -5\frac{1}{15}

The above value means that the diver's elevation is at -5\frac{1}{15} ft below the sea  level.

Read more about fractions at:

brainly.com/question/18134643

5 0
3 years ago
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