(3x^2)-18x+(2y^2)+16y+5=0
1 answer:
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Answer:
(1, -1), (5, -3)
Step-by-step explanation:
It is convenient to graph the solution space and plot the points.
You can also try the points in the inequality one by one (or all together).
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Here is the "all together" trial.
... {-3, 12, -2, -1, -3} - 2×{-6, 7, 0, 1, 5} ≤ -3 . . . . . use lists for x and y values
... {-3, 12, -2, -1, -3} - {-12, 14, 0, 2, 10} ≤ -3 . . . . multiply the x list by 2
... {9, -2, -2, -3, -13} ≤ -3 . . . . . . . . . . . . . . . . . . . . perform the subtraction
The inequality is true for the last two values, corresponding to points ...
... (1, -1) and (5, -3)
