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LenKa [72]
3 years ago
15

Write an algebraic expression for “5 times the sum of a number and 3”

Mathematics
1 answer:
Firdavs [7]3 years ago
3 0

Answer:

5(x+3)

Step-by-step explanation:

:)

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My product is 30. The differencd of the two factors is 1. The zum of the two factors is 11. What numbers am i
timurjin [86]
A * b = 30
a - b = 1
a + b = 11

take ur last 2 equations, and add them
a - b = 1
a + b = 11
--------------add
2a = 12
a = 12/2
a = 6

now its just a matter of subbing
a + b = 11
6 + b = 11
b = 11 - 6
b = 5

so a = 6 and b = 5...whose product is 30, whose difference is 1, and whose sum is 11.
5 0
3 years ago
Proport
Gwar [14]
It takes 5 minutes per square foot (400/180=5) and so 5 minutes per square for 720 squares: 720x5=3,600. 3,600 minutes is equivalent to 60 hours so it takes him 60 hours.
4 0
3 years ago
Read 2 more answers
Kathryn is 1.6 meters tall. Convert her height to feet. Round to the nearest tenth.
Andrej [43]

Answer:

1.6 m = 5.3 ft

4 0
3 years ago
25.6 × ? = 35.84. Please Help ASAP!!!​
xeze [42]

You have to divide both sides by the coefficient, which is 25.6.

Answer: 1.4

8 0
3 years ago
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Can someone please help me with this problem asap? Thanks!! :))
ivolga24 [154]

Answer: \$4.34

Step-by-step explanation:

We have the following information:

Fredburguer F, milkshake M and an order of fries f costs \$3.72:

F+M+f=\$3.72 (1)

One Fredburguer is equal to a milkshake plus orders of fries:

F=M+2f (2)

Three milshakes is equal to a Fredburguer plus an order of fries:

3M=F+f (3)

And we are asked: If we have a Fredburguer, a milkshake and two orders of fries, how much do we have to pay?

F+M+2f=x (4)

Well with the first three equations we have a system of equations to solve. Let's begin by isolating F from (3):

F=3M-f (5)

Making (2)=(5):

M+2f=3M-f (6)

Isolating f:

f=\frac{2}{3}M (7)

Substituting (7) in (2):

F=M+2(\frac{2}{3}M) (8)

Isolating F:

F=\frac{7}{3}M (9)

Substituting (7) and (9) in (1):

\frac{7}{3}M+M+\frac{2}{3}M=\$3.72 (10)

Isolating M:

M=\$0.93 (11) This is the cost of a Milkshake

Substituting (11) in (7):

f=\frac{2}{3}\$0.93 (12)

f=\$0.62 (13) This is the cost of an order of frieds

Substituting (11) in (9):

F=\frac{7}{3}\$0.93 (14)

F=\$2.17 (15) This is the cost of a Fredburguer

Substituting (11), (13) and  (15) in (4):

\$2.17+\$0.93+2(\$0.62)=x (16)

Finally:

x=\$4.34 This is the cost of a Fredburguer, a milkshake and two orders of fries

8 0
3 years ago
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