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3 years ago

PLEASE HELP!!! SHOW WORK!!!! Please do not take my points! Thank you!

Mathematics

2 answers:

Vikentia [17]3 years ago

8 0

Answer

1=8 2=9 3=8 4=9 5=8

Step-by-step explanation:

Julli [10]3 years ago

7 0

1.X=8 2.X= x=9
3. X=8

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bob has 76 pencils , he wants to put the same number into 12 different boxes. how many will be in each box

marusya05 [52]

Answer:

6, but 4 pencils will remain

Step-by-step explanation:

76/12=6 1/3

To find the remainder, multiply the decimal or fraction by the divisor. 1/3*12= 4. Four pencils remain with six in each box.

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3 years ago

Read 2 more answers

I'm trying to find out the number of how much it cost to wrap each present, day one 41 small gifts were wrapped and 45 large wer

Licemer1 [7]

Answer:

Small gift: $2

Large gift: $7

Step-by-step explanation:

Let x represent cost of wrapping each small gift and y represent cost of wrapping each large gift.

We have been given that day one 41 small gifts were wrapped and 45 large were wrapped equaling $397.

We can represent this information in an equation as:

$41x+45y=397...(1)$

We are also told that day two 30 small gifts were wrapped and 47 large were wrapped equaling $389. We can represent this information in an equation as:

$30x+47y=389...(2)$

From equation (1), we will get:

$x=\frac{397-45y}{41}$

Upon substituting this value in equation (2), we will get:

$30(\frac{397-45y}{41})+47y=389$

$\frac{11910-1350y}{41}+\frac{47*41y}{41}=389$

$\frac{11910-1350y+1927y}{41}=389$

$\frac{11910+577y}{41}=389$

$\frac{11910+577y}{41}\cdot 41=389\cdot 41$

$11910+577y=15949$

$11910-11910+577y=15949-11910$

$577y=4039$

$\frac{577y}{577}=\frac{4039}{577}$

$y=7$

Therefore, cost to wrap a large gift is $7.

Upon substituting $y=7$ in equation $x=\frac{397-45y}{41}$ , we will get:

$x=\frac{397-45(7)}{41}$

$x=\frac{397-315}{41}$

$x=\frac{82}{41}$

$x=2$

Therefore, cost to wrap a small gift is $2.

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