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3 years ago

What’s ur name person I don’t know?

Mathematics

2 answers:

fomenos3 years ago

8 0

Answer:

Nicoly

Step-by-step explanation:

because my mother put my name like this

never [62]3 years ago

5 0

Answer:

Liliana, can u mark brainliest.

Step-by-step explanation:

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HELP ASAP BOX AND WHISKEE PLOTS! WILL MARK BRAINLIEST!

podryga [215]

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Step-by-step explanation:

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What is the answer to <br> 8/12 = ?/3

Luda [366]

Answer:

2/3 is the answer.

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6 0

3 years ago

Read 2 more answers

I'd appreciate it if you'd help! :)

liberstina [14]

The answer to your question would be

m=100d+200

why?

Well it took her 2 days to drive 200 mile so she drives 100 miles per day.

since she is already gone 200 miles you just add 100 times the days it takes.

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3 0

4 years ago

According to the U.S. Census Bureau, 42% of men who worked at home were college graduates. In a sample of 480 women who worked a

Likurg_2 [28]

Answer:

1) $0.327 - 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.315$

The point estimate for the proportion of college graduates among women who work at home is 0.327

2) $0.327 - 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.315$

$0.327 + 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.339$

The 80% confidence interval is given by (0.315; 0.339)

Step-by-step explanation:

For this case we have the following info given:

$X = 157$ represent the women who worked at home who were college graduates

$n = 480$ the sample size selected

Part 1

In order to find the proportion of college graduates among women who work at home and we can use the following formula:

$\hat p=\frac{X}{n} = \frac{157}{480}= 0.327$

The point estimate for the proportion of college graduates among women who work at home is 0.327

Part 2

Construct an 80% confidence interval for the proportion of women who work at home who are college graduates. Round the answer to three decimal places. An 80% confidence interval for the proportion of women who work at home Is < p <

The confidence interval for the true proportion would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 80% confidence interval the value for the significance is $\alpha=1-0.8=0.2$ and $\alpha/2=0.1$ , the critical value would be given by:

$z_{\alpha/2}=0.539$

And replacing we goot:

$0.327 - 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.315$

$0.327 + 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.339$

The 80% confidence interval is given by (0.315; 0.339)

6 0

3 years ago