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GuDViN [60]
3 years ago
13

A test was given to a group of students. The grades and gender are summarized below

Mathematics
1 answer:
jasenka [17]3 years ago
4 0

Answer:

<h3>★ <u>11/30</u> is the right answer. ★</h3>

Step-by-step explanation:

  • Number of male students who got 'A' in the test is 11
  • Number of female students who got 'A' in the test is 19
  • Total students who got 'A' in the test is 30
  • Probability that the male student got an 'A' is P(A | male) = (Number of male students who got 'A' in the test)/(Number of total students who got 'A' in the test) = <em><u>11/30</u></em>
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Answer:

Simplify:

-4^2-5(1^3)

So you get:

-21\\

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which of the following answer choices describes all the transformation found in the cubic function f(x)=-(x+2)3-5
Alona [7]
The cubic function is f(x) = x^3

You need to perform three transformations to the cubic function to obtain
f(x) = - (x + 2)^3 - 5.

Those transfformations are:

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2) reflect f(x) = (x + 2)^3 across the x-axis to obtain f(x) = - (x + 2)^3

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4 years ago
You have $550 in a savings account that earns 3% simple interest each yaer. How much will be in your account in 10 years?
bija089 [108]
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Rate of interest per year = 3%
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Amount = P(1 + rt)
Where
p = principal amount
r = rate of interest
t = Time
Then
Amount = 550[1 + (3/100) * 10)]
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3 years ago
Write an equation in point-slope form for the line through the given point with the given slope. (-10, -6); m = -5/8
vekshin1
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Hope this helps!
4 0
3 years ago
A researcher would like to estimate p, the proportion of U.S. adults who support recognizing civil unions between gay or lesbian
Minchanka [31]

Answer:

Question 1:

(b) 4,445

Question 2:

(c) 2.1%

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Question 1:

We have no previous estimate for the population proportion, so we use \pi = 0.5.

The sample size is n for which M = 0.015. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.015 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.015\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.015}

(\sqrt{n})^2 = (\frac{1.96*0.5}{0.015})^2

n = 4268

Samples above this value should be used, and the smaller sample above this value is of 4445, so the answer is given by option b.

Question 2:

Now we find M for which n = 2222.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

M = 1.96\sqrt{\frac{0.5*0.5}{2222}}

M = 0.021

So 2.1%, and the correct answer is given by option c.

3 0
3 years ago
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