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3 years ago

A test was given to a group of students. The grades and gender are summarized below

Mathematics

1 answer:

jasenka [17]3 years ago

4 0

Answer:

<h3>★ <u>11/30</u> is the right answer. ★</h3>

Step-by-step explanation:

Number of male students who got 'A' in the test is 11
Number of female students who got 'A' in the test is 19
Total students who got 'A' in the test is 30
Probability that the male student got an 'A' is P(A | male) = (Number of male students who got 'A' in the test)/(Number of total students who got 'A' in the test) = <em><u>11/30</u></em>

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Utilize as propriedades das potências e resolva 2⁴ * 2⁷ * 2⁵

Lana71 [14]

Answer:

65536

Step-by-step explanation:

2 elevado a 4 é 16 e 2 elevado a 7 é 128 e 2 elevado a 5 é 32, multiplique-os e você obterá 65536

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3 years ago

1/2r+2(3/4r-1)=1/4r+6

bixtya [17]

I think r should equal 32/7

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4 years ago

The area of a regular octagon is 25 cm2 what is the area with the sides five times as large

marin [14]

125 cm2 is the answer

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3 years ago

Read 2 more answers

A standard weight known to weigh 10 grams. Some suspect bias in weights due to manufacturing process. To assess the accuracy of

notsponge [240]

Answer:

a) The 98% confidence interval for the mean weight is between 10.00409 grams and 10.00471 grams

b) 49 measurements are needed.

Step-by-step explanation:

Question a:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.98}{2} = 0.01$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.01 = 0.99$ , so Z = 2.327.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 2.327\frac{0.0003}{\sqrt{5}} = 0.00031$

The lower end of the interval is the sample mean subtracted by M. So it is 10.0044 - 0.00031 = 10.00409 grams

The upper end of the interval is the sample mean added to M. So it is 10 + 0.00031 = 10.00471 grams

The 98% confidence interval for the mean weight is between 10.00409 grams and 10.00471 grams.

(b) How many measurements must be averaged to get a margin of error of +/- 0.0001 with 98% confidence?

We have to find n for which M = 0.0001. So

$M = z\frac{\sigma}{\sqrt{n}}$

$0.0001 = 2.327\frac{0.0003}{\sqrt{n}}$

$0.0001\sqrt{n} = 2.327*0.0003$

$\sqrt{n} = \frac{2.327*0.0003}{0.0001}$

$(\sqrt{n})^2 = (\frac{2.327*0.0003}{0.0001})^2$

$n = 48.73$

Rounding up

49 measurements are needed.

7 0

3 years ago

The question is: "Without actually graphing, describe how the graph of y = ( -2^(x+17) ) - 4.3 is related to the graph of y = 2^

Leokris [45]

Answer:

The function has been flipped due to the negative in front.

The function has been shifted 17 units to the left.

The function has been shifted 4.3 units down.

Step-by-step explanation:

When functions are transformed there are a few simple rules:

Adding/subtracting inside the parenthesis to the input shifts the function left(+) and right(-).
Adding/subtracting outside the parenthesis to the output shifts the function up(+) and down(-).
Multiplying the function by a number less than 1 compresses it towards the x-axis.
Multiplying the function by a number greater than 1 stretches it away from the x-axis.
Multiplying by a negative flips the graph.

The graph of $(-2^{x+17}) -4.3$ compares to $2^x$ in the following ways:

The function has been flipped due to the negative in front.

The function has been shifted 17 units to the left.

The function has been shifted 4.3 units down.

4 0

3 years ago