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Lesechka [4]
3 years ago
6

Si sumamos el cuadrado de un número más el cuadruple del siguiente resulta 225 ¿De que número se trata?

Mathematics
1 answer:
Talja [164]3 years ago
5 0

Answer:

What does it say in english

Step-by-step explanation:

ill answer it in comments if you tell me what it says in english

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Alice searches for her term paper in her filing cabinet, which has several drawers. She knows thatshe left her term paper in dra
katen-ka-za [31]

You made a mistake with the probability p_{j}, which should be p_{i} in the last expression, so to be clear I will state the expression again.

So we want to solve the following:

Conditioned on this event, show that the probability that her paper is in drawer j, is given by:

(1) \frac{p_{j} }{1-d_{i}p_{i}  } , if j \neq i, and

(2) \frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i}  } , if j = i.

so we can say:

A is the event that you search drawer i and find nothing,

B is the event that you search drawer i and find the paper,

C_{k}  is the event that the paper is in drawer k, k = 1, ..., n.

this gives us:

P(B) = P(B \cap C_{i} ) = P(C_{i})P(B | C_{i} ) = d_{i} p_{i}

P(A) = 1 - P(B) = 1 - d_{i} p_{i}

Solution to Part (1):

if j \neq i, then P(A \cap C_{j} ) = P(C_{j} ),

this means that

P(C_{j} |A) = \frac{P(A \cap C_{j})}{P(A)}  = \frac{P(C_{j} )}{P(A)}  = \frac{p_{j} }{1-d_{i}p_{i}  }

as needed so part one is solved.

Solution to Part(2):

so we have now that if j = i, we get that:

P(C_{j}|A ) = \frac{P(A \cap C_{j})}{P(A)}

remember that:

P(A|C_{j} ) = \frac{P(A \cap C_{j})}{P(C_{j})}

this implies that:

P(A \cap C_{j}) = P(C_{j}) \cdot P(A|C_{j}) = p_{i} (1-d_{i} )

so we just need to combine the above relations to get:

P(C_{j}|A) = \frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i}  }

as needed so part two is solved.

8 0
4 years ago
Lets see who can answer this with no hesitation and of course in return I'll brainlist you.
inysia [295]

Answer:

24 x 1.24 = 29.76

$29.76

works?

7 0
3 years ago
The digits 5, 7, 1, and 9 are to be used in a roll number in a school. How
svetlana [45]

Answer:

1, 7, 5, 9
7, 1, 9, 5

9, 5, 1, 7

But there are about 10 possible combinations.

Step-by-step explanation:

6 0
3 years ago
How do you find the complex and real roots for x^4-3x^2+2=0
pogonyaev
X^4 - 3x^2 + 2 = 0
(x^2 - 2)(x^2 - 1) = 0

so either x^2 - 2 = 0  or x^2 - 1 = 0

so x^2 = 2 or x^2 = 1

so x = sqrt 2 , - sqrt2, 1 , -1   Answer

all the roots are real
6 0
4 years ago
What is the equation of a line that is parallel to the line y = 2x + 7 and passes through the point (–2, 4)?
IgorC [24]
The Answer Is: y=2x+8
3 0
3 years ago
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