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Readme [11.4K]
3 years ago
7

How do I rewrite this in vertex form? Y=2x^2-8x+9

Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
5 0

Complete the <u>square</u> on the right side of the <u>equation</u>

2(x-2)^2+1

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Tom purchased a 40lb. bag of dog food. Knowing that there are 16 ounces in a pound, how many ounces of dog food are in the bag?
yan [13]

Answer:

640 Oz

Step-by-step explanation:

1 Lb = 16 Oz

40 Lb • 16 Oz = 640 Oz

hope this helps

Mark brainliest

8 0
3 years ago
Read 2 more answers
What are the intercepts of the line?
Schach [20]
To solve your X int you substitute 0 for y.

X int-
-5x+9(0)=-18
-5x=-18
X= 18/5 and the coordínate is (18/5,0)

Then to solve for y int you substitute 0 for x.

-5(0)+9y=-18
9y=-18
Y= -2 and the coordinate is (0,-2)
3 0
3 years ago
Please help me answer thsi question
Rus_ich [418]
U autocorrect this as thsi too!? Omg
5 0
2 years ago
Two students, Ann and Max, factored the trinomial 4x2-6x -4. Ann factored it as 2(k 2xx+ 1) and Max factored it as (-2)4x+2), In
marishachu [46]

Given trinomial 4x^2-6x-4.

In order to factor a trinomial, we need to factor out greatest common factor (GCF).

In the given trinomial, we have terms 4x^2, -6x, -4.

We can see that all terms can be divided by a greatest number 2.

Therefore, greatest common factor would be 2 there.

We need to factor out 2 first.

On factoring out 2, we get

2(2x^2 -3x -2).

Now, we need to factor out trinomial 2x^2 -3x -2 now.

We can factor a trinomial by applying product sum rule.

We have a=2,b=-3,c=-2.

ac= 2*-2 = -4 and b=-3.

So, we need to find the factors of -4 that add upto -3.

Factors of -4 would be -4 and 1.

Let us replace -3x by -4x +1x in 2x^2 -3x -2 trinomial

2x^2 -3x -2 could be rewrite as 2x^2 -4x +1x -2.

Making it into two groups and factoring out GCF of each group.

We get

(2x^2 -4x) +(1x - 2)

2x(x-2) +1(x-2)

=(x-2)(2x+1)

Therefore, final factors of the trinomial is 2(x-2)(2x+1).

So, Ann factored form 2(x-2)(2x+1) is correct.

8 0
3 years ago
Calculate two iterations of Newton's Method for the function using the given initial guess. (Round your answers to four decimal
pickupchik [31]

Answer:

The first and second iteration of Newton's Method are 3 and \frac{11}{6}.

Step-by-step explanation:

The Newton's Method is a multi-step numerical method for continuous diffentiable function of the form f(x) = 0 based on the following formula:

x_{i+1} = x_{i} -\frac{f(x_{i})}{f'(x_{i})}

Where:

x_{i} - i-th Approximation, dimensionless.

x_{i+1} - (i+1)-th Approximation, dimensionless.

f(x_{i}) - Function evaluated at i-th Approximation, dimensionless.

f'(x_{i}) - First derivative evaluated at (i+1)-th Approximation, dimensionless.

Let be f(x) = x^{2}-8 and f'(x) = 2\cdot x, the resultant expression is:

x_{i+1} = x_{i} -\frac{x_{i}^{2}-8}{2\cdot x_{i}}

First iteration: (x_{1} = 2)

x_{2} = 2-\frac{2^{2}-8}{2\cdot (2)}

x_{2} = 2 + \frac{4}{4}

x_{2} = 3

Second iteration: (x_{2} = 3)

x_{3} = 3-\frac{3^{2}-8}{2\cdot (3)}

x_{3} = 2 - \frac{1}{6}

x_{3} = \frac{11}{6}

7 0
3 years ago
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