A car tries to tow a stranded van out of a ditch, and the car applies 300 N and pulls the van for 3 meters in less than a minute
1 answer:
Answer:
Work done, W = 900 Joules
Explanation:
It is given that,
Force applies by the car on the van, F = 300 N
The van pulls a distance of, d = 3 m
We need to find the work was done by the car on the car. We know that the product of force and distance is equal to the work done by the object i.e.
W = 900 Joules
So, the work done by the car on the van is 900 Joules. Hence, this is the required solution.
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Answer:
∆h = 0.071 m
Explanation:
I rename angle (θ) = angle(α)
First we are going to write two important equations to solve this problem :
Vy(t) and y(t)
We start by decomposing the speed in the direction ''y''
Vy in this problem will follow this equation =
where g is the gravity acceleration
This is equation (1)
For Y(t) :
We suppose yi = 0
This is equation (2)
We need the time in which Vy = 0 m/s so we use (1)
So in t = 0.675 s → Vy = 0. Now we calculate the y in which this happen using (2)
2.236 m is the maximum height from the shell (in which Vy=0 m/s)
Let's calculate now the height for t = 0.555 s
The height asked is
∆h = 2.236 m - 2.165 m = 0.071 m
