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77julia77 [94]
3 years ago
15

Which has a larger atomic radius, potassium or bromine, and why?

Chemistry
1 answer:
weeeeeb [17]3 years ago
7 0
Both Bromine with an atomic number of 35 and Potassium with an atomic number of 19 both belong to group 4.  The 'rule' is that the atomic radius increases across the group from Group One to Eight.  This can be proven true.

As you move across the a period from left to right, the amount shell remains the same however an electron is added on to the final orbital.  In the case of potassium which has only one shell on the final shell, that electron is shielded from the pull of the nucleus by the third shell of electrons and as such the shell is able to float further away from the rest of the shells thus making a larger atom on a whole.  In the case of Bromine the number of electrons it has on the fourth shell (one down from the octet) is pulled heavily toward the nucleus because the increase in the number of protons in the nucleus thus seeing where its shells are closer to the nucleus therefore contributing to a smaller atomic radius.

Just so that you will always remember this here is a picture to remind you always.

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Decide if the following definite article and noun agreement is CORRECT or INCORRECT <br> La mapa
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It's el mapa so the answer is incorrect. Even though mapa has an 'a' at the end, you will still use el.
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4 years ago
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What's the formula of mercury (I) dioxonitrate III​
steposvetlana [31]
<h2>Answer:</h2>

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7 0
3 years ago
Which item is the weakest acid on the chart?
serious [3.7K]
ANSWER: Milk

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3 0
3 years ago
What else is produced when sodium carbonate decomposes? Na2CO3 Na2O +
andriy [413]

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The decomposition of sodium carbonate is:

Na_2CO_3\rightarrow Na_2O+ CO_2

The decomposition of sodium bicarbonate, Na_2CO_3 will result in the formation of sodium oxide, Na_2O and carbon dioxide, CO_2.

Hence, carbon dioxide, CO_2 will produce with sodium oxide, Na_2O on decomposition of Na_2CO_3.

7 0
3 years ago
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Rank the compounds in each set in order of increasing acid strength.
Viktor [21]

Answer:

See explanation

Explanation:

For this question, we have to remember the effect of an atom with high <u>electronegativity</u> as "Br". If the "Br" atom is closer to the carboxylic acid group (COOH) we will have an <u>inductive effect</u>. Due to the electronegativity of Br, the electrons of the C-H bond would be to the Br, then this bond would be <u>weaker</u> and the compound will be more acid (because is easier to produce the hydronium ion H^+).

With this in mind, for A in the last compound, we have <u>2 Br atoms</u> near to the acid carboxylic group, so, we will have a high inductive effect, then the C-H would be weaker and we will have <u>more acidity</u>. Then we will have the compound with only 1 Br atom and finally, the last compound would be the one without Br atoms.

In B, the difference between the molecules is the <u>position</u> of the "Br" atom in the molecule. If the Br atom is closer to the acid group we will have a <u>higher inductive effect</u> and more <u>acidity</u>.

See figure 1

I hope it helps!

5 0
4 years ago
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