Evaluate 3/2y-3+5/3z when y=4 and z=3

How to reduce into simpler terms.?

Sveta_85 [38]

Answer:

The simplest form of the fraction $\frac{45}{100}$ is $\frac{9}{20}$ .

i.e.

$\frac{45}{100}=\frac{9}{20}$

Step-by-step explanation:

Here are some simple observations regarding how to reduce a fraction into simpler terms:

A fraction is reduced to lowest or simplest terms by finding an equivalent fraction in which the numerator and denominator are as small as possible.

In order to reduce a fraction to lowest or simplest terms, divide the numerator and denominator by their (GCF). Note that (GCF) is also called Greatest Common Factor .

So, lets take a sample fraction and reduce into simpler terms.

Considering the fraction

$\frac{45}{100}$

$\mathrm{Find\:a\:common\:factor\:of\:}45\mathrm{\:and\:}100\mathrm{\:in\:order\:to\:cancel\:it\:out}$

$\mathrm{Greatest\:Common\:Divisor\:of\:}45,\:100:\quad 5$

$\mathrm{Factor\:out\:}5\mathrm{\:from\:the\:numerator\:and\:the\:denominator}$

$45=5\cdot \:9\mathrm{,\:\quad }100=5\cdot \:20$

so

$\frac{45}{100}=\frac{5\cdot \:\:9}{5\cdot \:\:20}$

$\mathrm{Cancel\:the\:common\:factor:}\:5$

$=\frac{9}{20}$

Therefore, the simplest form of the fraction $\frac{45}{100}$ is $\frac{9}{20}$ .

i.e.

$\frac{45}{100}=\frac{9}{20}$

4 0

3 years ago

What is 8 weeks from June 30th

lbvjy [14]

Answer:

The answer is25th August

8 0

3 years ago

Matt and Anna Killian are frequent fliers on Fast-n-Go Airlines. They often fly between two cities that are a distance of 1980

Ymorist [56]

Answer:

y (plane speed) 400 miles/hr

x (wind speed) 40 miles/hr

Step-by-step explanation:

going into the wind make the plane flew 5,5 hours to get 1980 miles, implies the real travel speed was

1980 / 5,5 = 360 miles/hours, and at the same time is the result of:

speed plane (y) in direction A to B plus wind speed (x) in direction B to A. Notice opposites direction speed, so we have:

y + (-x) = 360 (1)

The return fly took 4,5 hours so 1980/4,5 = 440 miles/ hours as the result

Y + x = 440 (2)

We have a two equation with two variables system, It could be solved for any of the procedures. We will use the substitution method.

From equation (1) y + (-x) = 360 y - x = 360 y = 360 + x (1)

In the second equation

y + x = 440 then we replace y for its value as function of x

(360 + x ) + x = 440

Solving for x 360 + 2x = 440 or 2x = 440 – 360

x (440 - 360)/2

x = 40 miles/hr

X (wind speed ) = 40 miles/hr

And replacing the value of x in eq. (1) y = 360 + 40 = 400

Y (plane speed) = 400 miles /hr

3 0

3 years ago

Eva invests $6400 in a new savings account which earns 3.4 % annual interest, compounded continuously. What

cupoosta [38]

Answer:

$7821.74

Step-by-step explanation:

Eva invests $6400 in a new savings account which earns 3.4% annual interest, compounded continuously.

We have to find the value of her investment after 6 years,

Now, using the formula for the compound interest we can get the value of her investment.

So, it will be $V = 6400 (1 + \frac{3.4}{100} )^{6} = 7821.74$ Dollars (Approximate)

{Rounded to the nearest cent} (Answer)

7 0

3 years ago

Use two different methods to find an explain the formula for the area of a trapezoid that has parallel sides of length a and B a

evablogger [386]

Answer:

Formula of Trapezoid:

A = (a + b) × h / 2

The formula can be derived in different ways. for now, we have discussed two ways:

1. By using the formula of a triangle

2. By dividing into different sections

Step-by-step explanation:

1. By using the formula of a triangle

One of the ways to explain a formula for an area of a trapezoid using a formula for a triangle can be as follows.

Assume a trapezoid PQRS with lower base SR and upper base PQ (they are parallel) and sides PS and QR.

The image is attached below.

Connect vertices P and R with a diagonal.

Consider triangle ΔPQR as having a base PQ and an altitude from vertex R down to point M on base PQ (RM⊥PQ).

Its area is

S1= $\frac{1}{2} *PQ*RM$

Consider triangle ΔPRS as having a base SR and an altitude from vertex P up to point N on-base SR (PN⊥SR).

Its area is

S2= $\frac{1}{2} *SR*PN$

Altitudes RM and PN are equal and constitute the distance between two parallel bases PQ and SR.

They both are equal to the altitude of the trapezoid h.

Therefore, we can represent areas of our two triangles as

S1= $\frac{1}{2}*PQ*h$

S2= $\frac{1}{2}*SR*h$

Adding them together, we get the area of the whole trapezoid:

S=S1+S2= $\frac{1}{2} (PQ+SR)h,$

which is usually represented in words as "half-sum of the bases times the altitude".

2. By dividing into different sections

Trapezoid PQRS is shown below, with PQ parallel to RS.

Figure 1 - Trapezoid PQRS with PQ parallel to RS(image is attached below.)

We are going to derive the area of a trapezoid by dividing it into different sections.

If we drop another line from Q, then we will have two altitudes namely PT and QU.

Figure 2 - Trapezoid PQRS divided into two triangles and a rectangle. (image is attached below.)

From Figure 2, it is clear that Area of PQRS = Area of PST + Area of PQUT + Area of QRU. We have learned that the area of a triangle is the product of its base and altitude divided by 2, and the area of a rectangle is the product of its length and width. Hence, we can easily compute the area of PQRS. It is clear that

=> $A_{PQRS} = (\frac{ah}{2}) + b_{1}h + \frac{ch}{2}$