4 years ago

PLEASE HELP ME!!!! PLEASE

Mathematics

2 answers:

White raven [17]4 years ago

7 0

B

Hope I helped thanks so much!

tankabanditka [31]4 years ago

7 0

B let me know if you need anything else

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The area of a triangle is one half the base and times the height. If the area of the triangle is 16 square inches and the vase i

sergij07 [2.7K]

Step-by-step explanation:

so, yes, the area of a triangle is

baseline × height / 2

so, we have here

16 = 8 × height / 2 = 4 × height

height = 16/4 = 4 in.

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2 years ago

Still have to times it by 20%

Brut [27]

Times what by 20% ? If you can ask me the full question i would love to help!

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3 years ago

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3 years ago

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Answer:

(a x 4)+(a x 3)=7a

Step-by-step explanation:

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or does your question means something else??

3 0

3 years ago

Find [5(cos 330 degrees + I sin 330 degrees)]^3

earnstyle [38]

Given a complex number in the form:
$z= \rho [\cos \theta + i \sin \theta]$
The nth-power of this number, $z^n$ , can be calculated as follows:

- the modulus of $z^n$ is equal to the nth-power of the modulus of z, while the angle of $z^n$ is equal to n multiplied the angle of z, so:
$z^n = \rho^n [\cos n\theta + i \sin n\theta ]$
In our case, n=3, so $z^3$ is equal to
$z^3 = \rho^3 [\cos 3 \theta + i \sin 3 \theta ] = (5^3) [\cos (3 \cdot 330^{\circ}) + i \sin (3 \cdot 330^{\circ}) ]$ (1)
And since
$3 \cdot 330^{\circ} = 990^{\circ} = 2\pi +270^{\circ}$
and both sine and cosine are periodic in $2 \pi$ , (1) becomes
$z^3 = 125 [\cos 270^{\circ} + i \sin 270^{\circ} ]$

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4 years ago