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nikitadnepr [17]
3 years ago
14

A positively-charged object with a mass of 0.129 kg oscillates at the end of a spring, generating ELF (extremely low frequency)

radio waves that have a wavelength of 3.86 × 10^7 m. The frequency of these radio waves is the same as the frequency at which the object oscillates. What is the spring constant of the spring?
Physics
1 answer:
9966 [12]3 years ago
7 0

Answer:308 N/m

Explanation:

Given

mass\left ( m\right )=0.129 kg

wavelength\left ( \lambda \right )=3.86\times 10^7

We know frequency =\frac{c}{\lambda }=\frac{3\times 10^8}{3.86\tmes 10^7}

f=7.772 Hz

As the frequency of radio waves is same as the frequency at which object oscillates

f=\frac{1}{2\pi }\sqrt{\frac{k}{m}}

7.772=\frac{1}{2\pi }\sqrt{\frac{k}{0.129}}

7.772\times 2\times \pi =\sqrt{\frac{k}{0.129}}

k=307.70\approx 308 N/m

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