The momentum of each vehicle is (its mass) times (its speed).
Given parameters:
Duration of crash = 9min
Velocity before crash = 2000 yards per second
Unknown:
Acceleration of the plane = ?
Solution:
Acceleration is the change of velocity with time.
Acceleration =
where v is the final velocity
u is the initial velocity
t is the time taken
We need to convert the time into seconds from min;
60s = 1 min
So, 9min = 60 x 9 = 540s
So input the parameters and solve;
Acceleration =
= 3.7yards/s²
The acceleration of the plane is 3.7yards/s²
Answer:
you divide distance traveled by the time it takes to travel that distance. average speed. If your speed changes from 10 km/h to 6 km/h, you have a(n) ... 400 km. Suppose that the average speed your dog can run is 3 m/s. ... she drives her scooter 7 kilometres north. She stops for lunch and then drives 5 kilometres south.
i rlly dunno lma.o
Explanation:
Answer:
(A) Speed will be ![44.18\times 10^4m/sec](https://tex.z-dn.net/?f=44.18%5Ctimes%2010%5E4m%2Fsec)
(b) Change in kinetic energy =
Explanation:
We have given mass of proton ![m=1.67\times 10^{-27}kg](https://tex.z-dn.net/?f=m%3D1.67%5Ctimes%2010%5E%7B-27%7Dkg)
Acceleration of the proton ![a=2.50\times 10^{12}m/sec^2](https://tex.z-dn.net/?f=a%3D2.50%5Ctimes%2010%5E%7B12%7Dm%2Fsec%5E2)
Initial velocity u =
m/sec
Distance traveled by proton s = 3.90 cm = 0.039 m
(a) From third equation of motion we know that
![v^2=u^2+2as](https://tex.z-dn.net/?f=v%5E2%3Du%5E2%2B2as)
![v^2=(1.60\times 10^4)^2+2\times 2.5\times 10^{12}\times 0.039](https://tex.z-dn.net/?f=v%5E2%3D%281.60%5Ctimes%2010%5E4%29%5E2%2B2%5Ctimes%202.5%5Ctimes%2010%5E%7B12%7D%5Ctimes%200.039)
![v=44.18\times 10^4m/sec](https://tex.z-dn.net/?f=v%3D44.18%5Ctimes%2010%5E4m%2Fsec)
(b) Initial kinetic energy ![KE_I=\frac{1}{2}mv^2=\frac{1}{2}\times 1.67\times 10^{-27}\times (1.6\times 10^4)^2](https://tex.z-dn.net/?f=KE_I%3D%5Cfrac%7B1%7D%7B2%7Dmv%5E2%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%201.67%5Ctimes%2010%5E%7B-27%7D%5Ctimes%20%281.6%5Ctimes%2010%5E4%29%5E2)
Final kinetic energy ![KE_F=\frac{1}{2}mv^2=\frac{1}{2}\times 1.67\times 10^{-27}\times (44.18\times 10^4)^2](https://tex.z-dn.net/?f=KE_F%3D%5Cfrac%7B1%7D%7B2%7Dmv%5E2%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%201.67%5Ctimes%2010%5E%7B-27%7D%5Ctimes%20%2844.18%5Ctimes%2010%5E4%29%5E2)
So change in kinetic energy ![\Delta KE=KE_F-KE_I=\frac{1}{2}\times 1.6\times 10^{-27}\times 10^8\times (44.18^2-1.6^2)=1560\times 10^{-19}J](https://tex.z-dn.net/?f=%5CDelta%20KE%3DKE_F-KE_I%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%201.6%5Ctimes%2010%5E%7B-27%7D%5Ctimes%2010%5E8%5Ctimes%20%2844.18%5E2-1.6%5E2%29%3D1560%5Ctimes%2010%5E%7B-19%7DJ)
Answer:
A) Gravitational Force is greater in S.
B) Time taken to fall a given distance in air will be greater for F.
C) Both will take same time to fall in a vacuum.
D) Total force is greater in S.
Explanation:
(a) In this case, the gravitational force of S will be greater, because Newton's Second Law states that - F = ma, or weight =mg. g is constant. And mass of the solid metal is heavier.
(b) In this case, the time it will take for F to fall from a given distance in air will be greater than that of S, since the air resistance is not negligible (as in the case of S).
(c) In this, It will take same time for S and F because in a vacuum, there are no air particles, so there is no air resistance and gravity is the only force acting and so objects fall at the same rate in a vacuum.
(d) The total force will be greater in S than F because Force=ma and S is of heavier mass than F.