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2 years ago

What is the percent yield of LiCl if I produced 30.85g LiCl and my theoretical yield was calculated to be 35.40g LiCl?

Chemistry

1 answer:

marissa [1.9K]2 years ago

7 0

Answer:

87.15%

Explanation:

To find percent yield, we can use this simple equation

$\frac{Actual}{Theoretical} *100$

Where "Actual" is the amount in grams actually collected from the reaction, and "Theoretical" is, well, the theoretical amount that should have been produced.

They give us these values, so to find the percent yield, just plug the numbers in.

$\frac{30.85}{35.40} *100\\\\ =87.15$

So, the percent yield is 87.15%

An easy trick to remember how to do this is just to divide the smaller number by the bigger number and move the decimal back two places. If you have a percent yield greater than 100%, something is wrong in the reaction.

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Can someone please help a girl out and answer this plsss ...need this as soon as posible

Helga [31]

Answer:

the anwser would be B obtain energy

Explanation:

7 0

3 years ago

The thermite reaction reacts iron (III) oxide, Fe2O3, with aluminium powder,Al, the form aluminium oxide, Al2O3 and iron, Fe.

lara [203]

Answer:

This answer assumes that the strated "16.0g of iron" was meant to be 16.0 grams of iron(III) oxide.

Explanation:

To start, the thermite equation must be balanced.

I find:

1Fe2O3 + 2Al = 1Al2O3 + 2Fe

This tells us we need 2 moles of Al for every 1 mole of Fe2O3.

Now calculate the moles of each reactant:

Moles Fe2O3: 16.0 g/159.7 g/mole = 0.100 moles Fe2O3

Moles Al: 8.1 /26.98 g/mole = 0.300 moles Al

The balanced equation says that in order to react all of the Fe2O3 we'd need twice that amount (in moles) of the Al. (0.100 moles Fe2O3)*(2) = 0.200 moles Al.

Which of the two reactants is the limiting reagent?

We have more than enough moles of Al to react with 0.10 moles of Fe2O3. (We have 0.300 moles Al and all we need is 0.200 moles to react with the 0.10 moles of Fe2O3. Fe2O3 is the limiting reagent.

Calculate the maximum mass of iron of iron that could be formed using these quantities of reactants.

The balanced equation tells us that we will obtain 2 moles of Fe for every 1 mole of Fe2O3 consumed. Since Fe2O3 is the limiting reagent, we will assume that it completely reacts. That means 0.1 moles of Fe2O3 is reacted. Since we expect twice that many moles of Fe, we should obtain 0.200 moles of Fe. At 55.85 g/mole, we should obtain:

(0.200 moles Fe)*(55.85 g Fe/mole Fe) = 11.2 grams Fe

5 0

1 year ago

Photodissociation of ozone (O3) can be described as producing an oxygen atom with heat of formation 247.5 kJ/mol. However, in re

Lapatulllka [165]

Answer:

0.2193 μm

Explanation:

The reaction showing the Photodissociation of ozone (O3) is given below as:

O₃ + hv --------------------------> O₂ + O⁺

H° (142.9) (0) (438kJ/mol).

The first thing to do here is to determine the change in the enthalpy of the total reaction, this can be done by subtracting the change in the enthalpy of the reactant from the change in enthalpy in the product. Hence, we have:

ΔH° = [438 kJ/mol + 247.5 kJ/mol] - (142.9) = 542.6 KJ/mol.

This value, that is 542.6 KJ/mol will then be used in the determination of the value for the maximum wavelength that could cause this photodissociation.

Therefore, the maximum wavelength could cause this photodissociation ≤ h × c/ E = [ 1.199 × 10⁻⁴]/ 542.6 = 2.193 × 10⁻⁷ = 0.2193 μm

7 0

2 years ago

Which branch of chemistry specifically deals with quantitative analysis?

LUCKY_DIMON [66]

Answer:

analyitical

Explanation:

4 0

3 years ago

Read 2 more answers

A brick lies perilously close to the edge of the flat roof of a building. The roof edge is 50 ft above street level, and the bri

wel

Hey there!:

The potential energy is U = m*g*h

Substitute 560.0 J for U = m*g*h so, 560.0 = m*g*h

g = 9.8 m/s²

50 ft in meters :

1 ft = 0.3048 m

50 ft = 50 * 0.3048 => 15.24 m

m = 560.0 / g*h

m = 560.0 / 9.8 * 15.24

m = 560.0 / 149.352

m = 3.74 kg

35 ft in m : 35 * 0.3048 => 10.668 m

The change initial in potencial energy from point A to B is:

mg ( h1 - h2 ) = 3.74* ( 9.8 )* (15.24 - 10.668 )

=> 36.652 * ( 15.24 - 10.688 ) =

36.652 * 4.552 => 167.57 J

According to the conservation of energy

The change in potencial energy should be equal to the change in kinetic energy , so the , the change in kinetic energy is :

ΔK = 167.57 J

Hope that helps!

5 0

3 years ago